Question
Write the correct answer in the following:
In a frequency distribution, the mid value of a class is 10 and the width of the class is. The lower limit of the class is:
  1. 6
  2. 7
  3. 8
  4. 12

Answer

  1. 7
Solution:
Let x and y be the uppel and lower and lower class limit in a frequency distribution.
Now, mid value of a class $\frac{(\text{x}+\text{y})}{2}=10$ [given]
⇒ x + y = 20 ...(i)
Also, given that, width of class x - y = 6 ...(ii)
On adding Eqs. (i) and (ii), we get
2x = 20 + 6
⇒ 2x = 26
⇒ x = 13
On putting x = 13 in Eq. (i), we get
13 + y = 20
⇒ y = 7
Hence, the lower limit of the class is 7.

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