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Polynomials — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsPolynomials1 Mark
MCQ
Write the correct answer in the following:
$\sqrt{2}$ is a polynomial of degree.
  • A
    2
  • B
    0
  • C
    1
  • D
    $\frac{1}{2}$
✓

Answer

  1. 0
    Solution:
    $\sqrt{2}$ is a constant polynomial. The only term here is $\sqrt{2}$ which can be written as $\sqrt{2}\text{x}^\circ.$ So, the exponent of x is zero. Therefore, the degree of the polynomial is 0.

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