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Heron’s Formula — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsHeron’s Formula1 Mark
MCQ
Write the correct answer in the following: The area of an isosceles triangle having base $2\ cm$ and the length of one of the equal sides $4\ cm$, is:
  • ✓
    $\sqrt{15}\text{cm}^2$
  • B
    $\sqrt{\frac{15}{2}}\text{cm}^2$
  • C
    $2\sqrt{15}\text{cm}^2$
  • D
    $4\sqrt{15}\text{cm}^2$
✓

Answer

Correct option: A.
$\sqrt{15}\text{cm}^2$
Here, $\text{s}=\frac{4+4+2}{2}=5\text{cm}$
Area of $\triangle=\sqrt{5(5-2)(5-4)(5-4)}$
$=\sqrt{5\times3\times1\times1}=\sqrt{15}\text{cm}^2$

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