Write the equilibrium constant K for C H_3 COOH + H_2 O = H_3 O^ … - Vidyadip

MCQ

Write the equilibrium constant $K$ for $C{H_3}COOH + {H_2}O = {H_3}{O^ + } + C{H_3}CO{O^ - }$

A
$K = \frac{{[{H_3}{O^ + }][{H_2}O]}}{{[C{H_3}CO{O^ - }][C{H_3}COOH]}}$
✓
$K = \frac{{[{H_3}{O^ + }][C{H_3}CO{O^ - }]}}{{[{H_2}O][C{H_3}COOH]}}$
C
$K = \frac{{[{H_3}{O^ + }][{H_2}O]}}{{[C{H_3}COOH][C{H_3}CO{O^ - }]}}$
D
$K = \frac{{[{H_2}O][C{H_3}CO{O^ - }]}}{{[{H_2}O][C{H_3}COOH]}}$

✓

Answer

Correct option: B.

$K = \frac{{[{H_3}{O^ + }][C{H_3}CO{O^ - }]}}{{[{H_2}O][C{H_3}COOH]}}$

b
Equilibrium constants for this reaction is $K =\frac{\left[ H _3 O ^{+}\right]\left[ CH _3 COO ^{-}\right]}{\left[ H _2 O \right]\left[ CH _3 COOH \right]}$

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