Question
Write the expression for the de Broglie wavelength associated with a charged particle having charge ‘q’ and mass ‘m’, when it is accelerated by a potential V.
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Answer
de Broglie wavelength $\lambda = \frac{\text{h}}{\text{p}} = \frac{\text{h}}{\sqrt{2\text{mqV}}}$
Hint: $\text{W = K qV} = \frac{\text{P}^{2}}{2\text{m}}\text { or } \text{p}= \sqrt{2\text{mqV}}.$
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