Question
Write the expression to calculate maximum work done when $1$ mole of an ideal gas expands isothermally and reversibly from $V_1$ to $V_2$.
✓
Answer
$W _{\max }=-2.303 RT \log _{10} \frac{ V _2}{ V _1}$
where,
$W _{\text {max }}=$ Maximum work done,
$R =$ Gas constant,
$T =$ Temperature in Kelvin,
$V_2$ and $V_1=$ Final and initial volume respectively
where,
$W _{\text {max }}=$ Maximum work done,
$R =$ Gas constant,
$T =$ Temperature in Kelvin,
$V_2$ and $V_1=$ Final and initial volume respectively
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