Question
Write the first four terms of the AP, when the first term $a = -1$ and the common difference d = $\frac{1}{2}$
✓
Answer
$a = -1,$ $d = \frac{1}{2}$
First term $= a = -1$
Second term $= -1 + d$ $ = - 1 + \frac{1}{2} = - \frac{1}{2}$
Third term $ = - \frac{1}{2} + d = - \frac{1}{2} + \frac{1}{2} = 0$
Fourth term $= 0 + d$ $ = 0 + \frac{1}{2} = \frac{1}{2}$
Hence, the first four terms of the given AP are $-1,$ $ - \frac{1}{2},0,\frac{1}{2}$.
First term $= a = -1$
Second term $= -1 + d$ $ = - 1 + \frac{1}{2} = - \frac{1}{2}$
Third term $ = - \frac{1}{2} + d = - \frac{1}{2} + \frac{1}{2} = 0$
Fourth term $= 0 + d$ $ = 0 + \frac{1}{2} = \frac{1}{2}$
Hence, the first four terms of the given AP are $-1,$ $ - \frac{1}{2},0,\frac{1}{2}$.
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