Question
Write the isomers of the compound having formula C4H9Br.
✓
Answer
There is four isomers of the given compound.
- $\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{Br}$
1-bromobutane.
- $\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3\\ \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{CH}_3-\text{CH}-\text{CH}_2\text{Br}$
1-bromo-2-methylpropane.
- $\ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3\\ \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{CH}_3-\text{C}-\text{Br}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
2-bromo-2-methylpropane.
- $\text{CH}_3\text{CH}_2\text{CH}\text{Br}\text{CH}_3$
2-bromobutane.
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