
- ✓ethyl $-2-$ (chlorocarbonyl) benzoate
- Bethyl $-2-$ (chloro carbonyl) hexanoate
- C$2-$ (thoxycarbonyl) benzoyl chloride
- DNone of these

IUPAC name:- ethyl -$2$-( chlorocarbonyl) benzoate
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$1$ litre of mixture $X$ $+$ excess $BaC{l_2} \to Z$ Number of moles of $Y$ and $Z $ are
$\begin{array}{*{20}{c}}
{C{H_3} - C = CH - C{H_2}C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{CH{{(C{H_3})}_2}\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow[{(ii)\,{H_2}{O_2},O{H^ - }}]{{(i)\,{B_2}{H_6}}}[A]$$\xrightarrow[\Delta ]{{dil.\,{H_2}S{O_4}}}[B]$
${N_2}{H_4}\left( l \right) + 2{H_2}{O_2}\left( l \right) \to \mathop {{N_2}\left( g \right) + 4{H_2}O\left( l \right);}\limits_{{\Delta_r} H_1^o = - 818\,kJ/mol} $
${N_2}{H_4}\left( l \right) + {O_2}\left( g \right) \to \mathop {{N_2}\left( g \right) + 2{H_2}O\left( l \right);}\limits_{{\Delta _r}H_2^o = - 622\,kJ/mol} $
${H_2}\left( g \right) + \frac{1}{2}{O_2}\left( g \right) \to \mathop {{H_2}O\left( l \right);}\limits_{{\Delta _r}H_3^o = - 285\,kJ/mol} $
.......$kJ/mol$