Question
Write the Pythagorean triplet whose smallest number is 18.
✓
Answer
Given, smallest number is 18 .
$\therefore \quad 2 \text{m}=18~$ or $~\text{m}=9$
$\text{m}^2+1=9^2+1=81+1=82$
$\text{m}^2-1=9^2-1=81-1=80$
So, the Pythagorean triplet is $(18,80,82).$
$\therefore \quad 2 \text{m}=18~$ or $~\text{m}=9$
$\text{m}^2+1=9^2+1=81+1=82$
$\text{m}^2-1=9^2-1=81-1=80$
So, the Pythagorean triplet is $(18,80,82).$
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