Question
  1. Write two important differences between inductive effect and resonance effect.
  2. Give reasons to explain the following observations:
  1. Carbon atom number $2$ in $CH_3CH_2Cl$ has more positive charge than that in $CH_3-CH_2-Br$.
  2. $CH_3-CH=CH-CH=CH_2(I)$ is more stable than $CH_3-CH=CH-CH_2-CH=CH_2(II)$

Answer

  1.  
S. No
Inductive effect
Resonance effect
1.
It involves o electrons.
It involves $\pi-$ electrons or lone pair of electrons.
2.
It decreases with distance and vanishes after $4^{th}$ carbon atom.
It is all along the length if system is conjugated (alternate double bonds).
3.
It is shown by even non-planar compounds.
It is shown by only planar compounds.
  1.  
  1. Polarisation of $CH_3CH_2Cl$ and $CH_3CH_2$ Br can be shown as follows.
$\stackrel{\delta\delta+}{\text{CH}_3}-\stackrel{\delta+}{\text{CH}_2}-\stackrel{\delta-}{\text{Cl}}\ \ \ \ \ \ \ \ \stackrel{\delta\delta+}{\text{CH}_3}-\stackrel{\delta+}{\text{CH}_2}-\stackrel{\delta-}{\text{Br}}$

Chlorine is more electronegative than Bromine. C-Cl bond is more polar than C-Br bond. Hence, inductive effect of 'Cl' is greater on the second carbon than Br.
  1. Resonating structures of (I)


It is more stable due to resonance effect due to conjugation i.e., alternate double bonds than II in which there is no resonance due to absence of conjugation.

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