MCQ
${{(x - a)(x - b)} \over {(x - c)(x - d)}} = {A \over {x - c}} - {B \over {(x - d)}} + C$, then $C =$
- A$5$
- B$4$
- C$3$
- ✓$1$
Equating coefficient of ${x^2},\,C = 1$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$a_n=\frac{\alpha^n-\beta^n}{\alpha-\beta}, n \geq 1$
$b_1=1 \text { and } b_n=a_{n-1}+a_{n+1}, n \geq 2.$
Then which of the following options is/are correct?
$(1)$ $a_1+a_2+a_3+\ldots . .+a_n=a_{n+2}-1$ for all $n \geq 1$
$(2)$ $\sum_{n=1}^{\infty} \frac{ a _{ n }}{10^{ n }}=\frac{10}{89}$
$(3)$ $\sum_{n=1}^{\infty} \frac{b_n}{10^n}=\frac{8}{89}$
$(4)$ $b=\alpha^n+\beta^n$ for all $n>1$