MCQ
$X$ in the above reaction is


- A$HN{O_3}$
- B${O_2}$
- C${O_3}$
- ✓$KMn{O_4}$


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(At. No. $Ti = 22, V = 23, Cr = 24, Mn = 25$)
(Round off to the Nearest Integer).
(Round off to the Nearest Integer) [Given : $R =8.314 \,J mol ^{-1} K ^{-1}$. Assume,
hydrogen is an ideal gas] [Atomic mass off $Fe$ is $55.85\, u$ ]