Question
$X$ is a normal variate such that for its value $x_{1}=90$ and $x_{2}=126$ the corresponding $z$-values are $z_{1}=-0.6$ and $z_{2}=1.2$. Obtain the values of the parameters of normal distribution. State the probability density function of $X$.$f(x)=\frac{1}{20 \sqrt{2 \pi}} e^{-\frac{1}{2}\left(\frac{x-102}{20}\right)^{2}}$

Answer

$f(x) = \frac{1}{20\sqrt{2 π}}e^{-\frac{1}{2}(\frac{x-102}{20})^2}$

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