MCQ
$XeF_2$ and $XeF_6$ are separately hydrolysed then;
- Aboth give out $O_2$
- B$XeF_6$ gives $O_2$ and $XeF_2$ does not
- ✓$XeF_2$ alone gives $O_2$
- DNeither of them gives $HF$
✓
Answer
Correct option: C.
$XeF_2$ alone gives $O_2$
c
$\text{Xe}{{\text{F}}_{2}}+{{\text{H}}_{2}}\text{O}\xrightarrow{R.T.}\text{Xe}+2\text{HF}+\frac{1}{2}{{\text{O}}_{2}}\uparrow $
$\text{Xe}{{\text{F}}_{2}}+{{\text{H}}_{2}}\text{O}\xrightarrow{R.T.}\text{Xe}+2\text{HF}+\frac{1}{2}{{\text{O}}_{2}}\uparrow $
$\mathrm{XeF}_{6}+3 \mathrm{H}_2O \stackrel{\mathrm{R.T}}{\longrightarrow} \mathrm{XeO}_{3}+6 \mathrm{HF}$
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