y = 2, (cm), sin,left[ {frac{{pi t}}{2} + phi } right] what is the maximum acceleration of the particle doing the S.H.M.

Q: $y = 2\, (cm)\, sin\,\left[ {\frac{{\pi t}}{2} + \phi } \right]$ what is the maximum acceleration of the particle doing the $S.H.M.$

b $y = 2\,\sin \,\left( {\frac{{\pi t}}{2} + \phi } \right)$ velocity of particle $\frac{{dy}}{{dt}} = 2 \times \frac{\pi }{2}\,\cos \,\left( {\frac{{\pi t}}{2} + \phi } \right)$ acceleration $\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dt}}=-\frac{\pi^{2}}{2} \sin \left(\frac{\pi \mathrm{t}}{2}+\phi\right)$ Thus $a_{\max }=\frac{\pi^{2}}{2}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

$y = 2\, (cm)\, sin\,\left[ {\frac{{\pi t}}{2} + \phi } \right]$ what is the maximum acceleration of the particle doing the $S.H.M.$

A$\frac{\pi }{2}\,cm/s^2$
B$\frac{\pi^2 }{2}\,cm/s^2$
C$\frac{\pi^2 }{4}\,cm/s^2$
D$\frac{\pi }{4}\,cm/s^2$

AIIMS 2014, Medium

STD 11 Science
NEET
STD 11 - 13. oscillations
Physics

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