M.C.Q [1M]

MCQ 11 Mark

Which of the following alcohols will not undergo oxidation?

A
Butan-2-ol
✓
2-Methylbutan-2-ol
C
Butanol
D
3-Methylbutan-2-ol

Answer

Correct option: B.

2-Methylbutan-2-ol

(b) 2-Methylbutan-2-ol
Explanation: 2-Methylbutan-2-ol will not undergo oxidation.

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MCQ 21 Mark

The slope in the plot of log $\frac{[ R ]_0}{[ R ]}$ vs. time for a first order reaction is

A
$-k$
B
$\frac{- k }{2.303}$
✓
$\frac{+ k }{2.303}$
D
$+ k$

Answer

Correct option: C.

$\frac{+ k }{2.303}$

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MCQ 31 Mark

Match the items given in column I with that in column II:

Column I	Column II
(a) Osmotic Pressure.	(i) Cottrell's method.
(b) Relative lowering of vapour pressure.	(ii) Rast's method.
(c) Elevation in boiling point.	(iii) Ostwald and Walker's method.
(d) Depression in freezing point.	(iv) Berkeley and Hartley's method.

✓
(a) (iv), (b) - (iii), (c) - (i), (d) - (ii).
B
(a) (iv), (b) - (iii), (c) - (ii), (d) - (i).
C
(a) (i), (b) - (ii), (c) - (iii), (d) - (iv).
D
(a) (i), (b) - (iv), (c) - (ii), (d) - (iii).

Answer

Correct option: A.

(a) (iv), (b) - (iii), (c) - (i), (d) - (ii).

(a) (a) (iv), (b) - (iii), (c) - (i), (d) - (ii).
Explanation: (a) (iv), (b) (iii), (c) - (i), (d) - (ii).

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MCQ 41 Mark

Which of the following reactions is a halogenated exchange reaction:

Answer

Correct option: D.

(d)

Explanation:

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MCQ 51 Mark

What is the correct IUPAC name of the given compound?

A
2-Carboxyl-2-methylbutane
B
2-Ethyl-2-methylpropanoic acid
C
3-Methylbutane carboxylic acid
✓
2,2-Dimethylbutanoic acid

Answer

Correct option: D.

2,2-Dimethylbutanoic acid

(d) 2,2-Dimethylbutanoic acid
Explanation: 2,2-Dimethylbutanoic acid

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MCQ 61 Mark

When 10 g of radioactive isotope is reduced to 1.25 g in 12 years, the half life period of the isotope is

✓
4 years
B
24 years
C
16 years
D
8 years

Answer

Correct option: A.

4 years

(a) 4 years
Explanation: Radioactivity follow 1st order kinetics. $
\begin{array}{l}
k=\frac{2.303}{t} \log \frac{a}{a-x} \\
k=\frac{2.303}{12} \log \frac{10}{1.25} \\
k=0.1919 \log 8 \\
k=0.1919 \times \log 2^3 \\
k=0.1919 \times 3 \times \log 2=0.575 \times 0.3010=0.173 yr^{-1}
\end{array}
$
now,
$
t_{1 / 2}=\frac{0.693}{0.173}=4.005 yrs \simeq 4 yrs
$

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MCQ 71 Mark

An organic compound X is oxidized by using acidified K₂Cr₂O₇. The product obtained reacts with Phenyl hydrazine but does not answer the silver mirror test. The possible structure of X is:

✓
(CH₃)₂CHOH
B
(CH₄)₂CH₃OH
C
CH₃CHO
D
CH₃CH₂OH

Answer

Correct option: A.

(CH₃)₂CHOH

(a) (CH₃)₂CHOH
Explanation: Secondary alcohol on oxidation forms ketone which reacts with hydrazine bus doesn't gives a silver mirror test.

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MCQ 81 Mark

The major component of starch is:

✓
amylopectin
B
water
C
amylose
D
glucose

Answer

Correct option: A.

amylopectin

(a) amylopectin
Explanation: Starch is a polymer of a-glucose and consists of two components - Amylose and Amylopectin. Amylose is water-soluble component which constitutes about 15-20% of starch. Amylopectin is insoluble in water and constitutes about 80-85% of starch. Thus, Amylopectin is the major component of starch.

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MCQ 91 Mark

When Benzene diazonium chloride reacts with phenol, it forms a dye. This reaction is called