Question 11 Mark
A 60 µF capacitor is connected to a 110V, 60 Hz ac supply. Determine the rms value of the current in the circuit.
Answer
View full question & answer→Given : $C=60 \mu F=60 \times 10^{-6} F$
$E _{ rms }=110 V$
$f=60 Hz$
$I _{ rms }=?$
$I_{r m s}=\frac{E_{r m s}}{X_C}=\omega C E_{r m s} \quad\left(\because X_C=\frac{1}{\omega C}\right)$
$\therefore \quad I _{ rms }=2 \pi f C E _{ rms }$
$=2 \times 3.14 \times 60 \times 60 \times 10^{-6} \times 110$
$=2.49 A$
$E _{ rms }=110 V$
$f=60 Hz$
$I _{ rms }=?$
$I_{r m s}=\frac{E_{r m s}}{X_C}=\omega C E_{r m s} \quad\left(\because X_C=\frac{1}{\omega C}\right)$
$\therefore \quad I _{ rms }=2 \pi f C E _{ rms }$
$=2 \times 3.14 \times 60 \times 60 \times 10^{-6} \times 110$
$=2.49 A$
