Half-life of radioactive substance is :
- A$0.6931 \times \lambda$
- B$\frac{\log 10^2}{\lambda}$
- ✓$\frac{0.6931}{\lambda}$
- D$\frac{\text { Average age }}{0.6931}$
Answer: C.
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M.C.Q [1M]
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Answer: C.
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