Question 12 Marks
An object 1cm tall is placed 30cm in front of a convex mirror of focal length 20cm. Find the size and position of the image formed by the convex mirror.
Answer
View full question & answer→$h _1=1 cm, u =-30 cm, f =20 cm, h _2=?, v =?$
$\frac{1}{\text{v}}+\frac{1}{\text{u}}=\frac{1}{\text{f}}$
$\frac{1}{\text{v}}+\frac{1}{-30}=\frac{1}{20}$
$\frac{1}{\text{v}}=\frac{1}{30}+\frac{1}{20}$
$\text{v}=12\text{cm}$
The image is formed 12cm behind the mirror.
$\text{m}=-\frac{\text{v}}{\text{u}}=\frac{\text{h}_2}{\text{h}_1}$
$\text{m}=-\frac{12}{-30}=\frac{\text{h}_2}{14}$
${\text{h}_2}=0.4\text{cm}$
$\frac{1}{\text{v}}+\frac{1}{\text{u}}=\frac{1}{\text{f}}$
$\frac{1}{\text{v}}+\frac{1}{-30}=\frac{1}{20}$
$\frac{1}{\text{v}}=\frac{1}{30}+\frac{1}{20}$
$\text{v}=12\text{cm}$
The image is formed 12cm behind the mirror.
$\text{m}=-\frac{\text{v}}{\text{u}}=\frac{\text{h}_2}{\text{h}_1}$
$\text{m}=-\frac{12}{-30}=\frac{\text{h}_2}{14}$
${\text{h}_2}=0.4\text{cm}$
The image is real, inverted and magnified. It is formed beyond the centre of curvature of the mirror.

All the light rays which are parallel to the principal axis of a concave mirror, converge at the the principal focus (F) after reflection from the mirror. Since a concave mirror converges a parallel beam of light rays, it is also called a converging mirror.
Because while driving our car. if we see in our rear-view mirror that the hospital van is coming from behind, then we get the laterally inverted image of
and read its as AMBULANCE and give way for it to pass throught.
For obtaining an enlarged upright image of an object, the object is placed between focus (F).

All the light rays which are parallel to the principal axis of a convex mirror, appear to diverge from the principal focus (F) after reflection from the mirror. Since a convex mirror diverges a parallel beam of light rays, it is also called a diverging mirror.