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8 questions · timed · auto-graded

MCQ 11 Mark
$\log (1 \times 2 \times 3)$ is equal to
  • $\log 1+\log 2+\log 3$
  • B
    $\log 3$
  • C
    $\log 2$
  • D
    none of these
Answer
Correct option: A.
$\log 1+\log 2+\log 3$
(A) $\log 1+\log 2+\log 3$
Explanation : Since, $\log _a(m n)=\log _a m+\log _a n$
One extending this rule for three variables, we get$
\log _a(m n p)=\log _a m+\log _a n+\log _a p
$
Therefore, $\log (1 \times 2 \times 3)=\log 1+\log 2+\log 3$.
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MCQ 21 Mark
$\log \left(\frac{32}{4}\right)$ is equal to
  • A
    $\frac{\log 32}{\log 4}$
  • $\log 32-\log 4$
  • C
    $2^3$
  • D
    none of these
Answer
Correct option: B.
$\log 32-\log 4$
(B) $\log 32-\log 4$
Explanation : We know that,
$
\log _a\left(\frac{m}{n}\right)=\log _a m-\log _a n
$
Therefore, $\log \left(\frac{32}{4}\right)=\log 32-\log 4$
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MCQ 31 Mark
$\log _2 8$ is equal to
  • A
    2
  • B
    8
  • 3
  • D
    none of these
Answer
Correct option: C.
3
(C) 3
Explanation: $\log _2 8=\log _2\left(2^3\right)=3 \log _2 2=3$
[Applying rules $\log _a m^n=n \log _a m$ and $\log _a a=1$ ]
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MCQ 41 Mark
$\log 6+\log 5$ is expressed as
  • A
    $\log 11$
  • $\log 30$
  • C
    $\log \frac{5}{6}$
  • D
    none of these
Answer
Correct option: B.
$\log 30$
(B) $\log 30$
Explanation : We know that
$\log _a(m n)=\log _a m+\log _a n$
Therefore, $\log 6+\log 5=\log (6 \times 5)=\log 30$
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MCQ 51 Mark
Which is true?
  • A
    $2^0>\left(\frac{1}{2}\right)^0$
  • B
    $2^0<\left(\frac{1}{2}\right)^0$
  • $2^0=\left(\frac{1}{2}\right)^0$
  • D
    none of these
Answer
Correct option: C.
$2^0=\left(\frac{1}{2}\right)^0$
(C) $2^0=\left(\frac{1}{2}\right)^0$
Explanation : According to zero index rule,$
\begin{aligned}
& 2^0=1 \text { and }\left(\frac{1}{2}\right)^0=1 \\
\therefore & 2^0=\left(\frac{1}{2}\right)^0
\end{aligned}
$
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MCQ 61 Mark
$3.2^{1 / 2} \cdot 4^{3 / 4}$ is equal to
  • A
    a fraction
  • a positive integer
  • C
    a negative integer
  • D
    none of these
Answer
Correct option: B.
a positive integer
(B) a positive integer
Explanation : $2^{\frac{1}{2}} \cdot 4^{\frac{3}{4}}=2^{\frac{1}{2}} \cdot\left(2^2\right)^{3 / 4}$
$\begin{array}{r}=2^{\frac{1}{2}} \cdot 2^{2 \times \frac{3}{4}} \\ \quad\left[ U \operatorname{sing}\left(a^{m}\right)^n=a^{m n}\right]\end{array}$
$\begin{array}{l}=2^{\frac{1}{2}} \cdot 2^{\frac{3}{2}} \\ =2^{\frac{1}{2}+\frac{3}{2}}=2^{\frac{4}{2}}=2^2=4 \\ \quad\left[\text { Using } a^m \times a^n=a^{m+n}\right]\end{array}$
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MCQ 71 Mark
The value of $8^{1 / 3}$ is
  • A
    $\sqrt[3]{2}$
  • B
    4
  • 2
  • D
    none of these
Answer
Correct option: C.
2
(C) 2
Explanation : $(8)^{1 / 3}=\left(2^3\right)^{1 / 3}=2^1=2$.
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MCQ 81 Mark
$4 x^{-1 / 4}$ is expressed as
  • A
    $-4 x^{1 / 4}$
  • B
    $x^{-1}$
  • $\frac{4}{x^{1 / 4}}$
  • D
    none of these
Answer
Correct option: C.
$\frac{4}{x^{1 / 4}}$
(C) $\frac{4}{x^{1 / 4}}$
Explanation : $4 x^{-1 / 4}=\frac{4}{x^{1 / 4}}$ (negative index rule)
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MCQ - Applied Maths STD 11 Science Questions - Vidyadip