Question 14 Marks
| Column-I | Column-II |
| (a) Inverse of implication $p \Rightarrow q$ | (i) $\sim p \wedge \sim q$ |
| (b) Negation of implication $p \Rightarrow q$ | (ii) $\sim p \Rightarrow \sim q$ |
| (c) $\sim(p \vee q)$ is equal to | (iii) $\sim p \vee \sim q$ |
| (d) $\sim(p \wedge q)$ is equal to | (iv) $p \wedge \sim q$ |
Answer
View full question & answer→(a) ↔ (ii), (b) ↔ (iv), (c) ↔ (i), (d) ↔ (iii).