MCQ 11 Mark
For two non empty sets A and B the Cartesian product is
- A$\mathrm{A} \times \mathrm{B}=\phi=\mathrm{B} \times \mathrm{A}$
- B$\mathrm{A} \times \mathrm{B} \neq \mathrm{B} \times \mathrm{A}$
- C$A \times B=B \times A$
- D$\mathrm{A} \times \mathrm{B}=\mathrm{B} \neq \mathrm{A}$
Answer
View full question & answer→(b) $\mathrm{A} \times \mathrm{B} \neq \mathrm{B} \times \mathrm{A}$
Explanation: let $\mathrm{A}=\{\mathrm{a}, \mathrm{b}, \mathrm{c}\} ; \mathrm{B}=\{\mathrm{p}\}$
$A \times B=\{a, b, c\} \times\{p\}$
$=\{(\mathrm{a}, \mathrm{p}),(\mathrm{b}, \mathrm{p}),(\mathrm{c}, \mathrm{p})\}$
$B \times A=\{p\} \times\{a, b, c\}$
$=\{(p, a),(p, b),(p, c)\}$
By the definition of ordered pairs, $(a, p) \neq(p, a)$
So $A \times B \neq B \times A$
Explanation: let $\mathrm{A}=\{\mathrm{a}, \mathrm{b}, \mathrm{c}\} ; \mathrm{B}=\{\mathrm{p}\}$
$A \times B=\{a, b, c\} \times\{p\}$
$=\{(\mathrm{a}, \mathrm{p}),(\mathrm{b}, \mathrm{p}),(\mathrm{c}, \mathrm{p})\}$
$B \times A=\{p\} \times\{a, b, c\}$
$=\{(p, a),(p, b),(p, c)\}$
By the definition of ordered pairs, $(a, p) \neq(p, a)$
So $A \times B \neq B \times A$