MCQ - Applied Maths STD 11 Science Questions - Vidyadip

Questions

MCQ

🎯

Test yourself on this topic

18 questions · timed · auto-graded

MCQ 11 Mark

If $\mathrm{A}=\left\{\mathrm{x}: \mathrm{x}^{2}-5 \mathrm{x}+6=0\right\}, \mathrm{B}=\{2,4\}, \mathrm{C}=\{4,5\}$ then $A \times(B \cap C)$ is

A
$\{(4,2),(4,3)\}$
B
$\{(2,2),(3,3),(4,4),(5,5)\}$
C
$\{(2,4),(3,4),(4,4)\}$
✓
$\{(2,4),(3,4)\}$

Answer

Correct option: D.

$\{(2,4),(3,4)\}$

(d) $\{(2,4),(3,4)\}$
Explanation: $x^{2}-5 x+6=0$
$\Rightarrow \mathrm{x}^{2}-2 \mathrm{x}-3 \mathrm{x}+6=0$
$\Rightarrow \mathrm{x}(\mathrm{x}-2)-3(\mathrm{x}-2)=0$
$\Rightarrow(\mathrm{x}-3)(\mathrm{x}-2)=0$
$\therefore A=\{2,3\} ;$ Also, $B=\{2,4\}, c=\{4,5\}$
Now, $B \cap C=\{4\}$
$\therefore A \times B \cap C=\{2,3\} \times\{4\}$
$=\{(2,4),(3,4)\}$

View full question & answer→

MCQ 21 Mark

Which of the following is not a binary number?

✓
11 E
B
000
C
1111
D
101

Answer

Correct option: A.

11 E

(a) 11 E
Explanation: A binary number can have only two possible digits 0 and 1 . Option 11E, there is an alphabet $E$ present which makes it invalid binary number. Alphabets are only allowed in the hexadecimal number system.

View full question & answer→

MCQ 31 Mark

What sum must be invested at the end of each year to provide funds for the replacement of a machine costing ₹ 8000 at the end of 3 years, if money is worth $5 \%$ effective? (Given $(1.05)^{3}=1.1576$ )

A
₹ 3042.07
B
₹ 2737.67
✓
₹ 2538.07
D
₹ 2832.67

Answer

Correct option: C.

₹ 2538.07

(c) ₹ 2538.07
Explanation: Let R be the sum invested at the end of every year for 3 year which amounts to ₹ 8000 and $\mathrm{i}=0.05$
$\therefore \mathrm{R}\left[\frac{(1.05)^{3}-1}{0.05}\right]=8000$
$\Rightarrow \mathrm{R}=\frac{8000 \times 0.05}{(1.1576-1)}=\frac{8000 \times 0.05}{0.1576}=₹ 2538.07$

View full question & answer→

MCQ 41 Mark

The probability that in the toss of two dice we obtain the sum 7 or 11 is:

A
$\frac{1}{18}$
✓
$\frac{2}{9}$
C
$\frac{23}{108}$
D
$\frac{1}{6}$

Answer

Correct option: B.

$\frac{2}{9}$

(b) $\frac{2}{9}$
Explanation: By throwing 7 we mean a sum of 7.
Now the first die may appear in 6 different ways and according to any one way in which the first appearance, the second can appear in 6 ways,
The two dice, therefore, may appear in $6 \times 6=36$ ways. favourable ways of getting a sum of 7 are $(1,6),(6,1),(2,5),(5,2)$, $(3,4),(4,3)$.
Thus the sum of 7 may appear in 6 different ways. i.e $p_{1}$ (probability of getting the sum of 7 ) $=\frac{6}{36}=\frac{1}{6}$
The sum of 11 may appear as $5+6,6+5$ i.e. in 2 different ways.
$\therefore \mathrm{p}_{2}$ (probability of getting the sum of 11 ) $=\frac{2}{36}=\frac{1}{18}$
Hence the probability of 7 or $11=\frac{1}{6}+\frac{1}{18}=\frac{4}{18}=\frac{2}{9}$

View full question & answer→

MCQ 51 Mark

If $\frac{\log x}{a-b}=\frac{\log y}{b-c}=\frac{\log z}{c-a}$, then xyz is equal to:

A
2
B
0
✓
1
D
-1

Answer

Correct option: C.

1

(c) 1
Explanation: 1

View full question & answer→

MCQ 61 Mark

Deduction of Medical Insurance Premium is allowed under section ______.

A
80 C
B
80 TTA
C
80 E
✓
80 D

Answer

Correct option: D.

80 D

(d) 80 D
Explanation: Deduction on Section 80D in Income Tax Act. You are allowed to claim a deduction up to Rs. 25,000 per budgetary year for medical insurance premium instalments.

View full question & answer→

MCQ 71 Mark

Sanjay buys land for 200000 and agrees to pay an equal amount at the end of each year for 3 years. If the money is worth $8 \%$, then the amount of each instalment is: $\left(\right.$ Given $\left.(1.08)^{-3}=0.7938\right)$.

A
₹ 78895.12
B
₹ 75323.48
C
₹ 75428.56
✓
₹ 77594.56

Answer

Correct option: D.

₹ 77594.56

(d) ₹ 77594.56
Explanation: Present value $=₹ 200000$, time $=3$ years, $\mathrm{i}=0.08$ Let each instalment be of ₹ R .
$\therefore$ It forms an annuity.
$\therefore ₹ 200000=\mathrm{R}\left[\frac{1-(1.08)^{-3}}{0.08}\right]$
$\Rightarrow \mathrm{R}=\frac{200000 \times 0.08}{1-0.7938}=\frac{200000 \times 0.08}{0.2062}=₹ 77594.56$

View full question & answer→

MCQ 81 Mark

If $\log 0.0007392=-3.1313$, then $\log 73.92$ is

✓
1.8687
B
2.8687
C
1.1313
D
2.1313

Answer

Correct option: A.

1.8687

(a) 1.8687
Explanation: $\log 0.0007392=-3.1313=-4+4-3.1313=-4+0.8687$
$\Rightarrow \log 0.0007392=\overline{4} .8687$
$\Rightarrow$ mantissa of digits $7392=0.8687$
$\therefore \log 73.92=1.8687(\because$ Characteristic of $\log 73.92=1)$

View full question & answer→

MCQ 91 Mark

The mean deviation of the data $2,9,9,3,6,9,4$ from the mean is

A
3.57
✓
2.57
C
2.23
D
3.23

Answer

Correct option: B.

2.57

(b) 2.57
Explanation: M.D. $(\bar{x})=\frac{\left|x_{i}-\bar{x}\right|}{n}=\frac{4+3+3+3+0+3+2}{7}=2.57$

View full question & answer→

MCQ 101 Mark

If CASUAL represents FXVRDI, then PEOPLE in coded language represents

A
$\operatorname{SHRSQH}$
B
SBRMPB
✓
SBRMOB
D
SHRSOH

Answer

Correct option: C.

SBRMOB

(c) SBRMOB
Explanation: CASUAL $\leftrightarrow$ FXVRDI
$\mathrm{C} \xrightarrow{+3} \mathrm{~F} ; \mathrm{A} \xrightarrow{-3} \mathrm{X} ; \mathrm{S} \xrightarrow{+3} \mathrm{~V} ; \mathrm{U} \xrightarrow{-3} \mathrm{R} ; \mathrm{A} \xrightarrow{+3} \mathrm{D} ; \mathrm{L} \xrightarrow{-3} \mathrm{I}$
PEOPLE $\mathrm{P} \xrightarrow{+3} \mathrm{E} ; \mathrm{C} \xrightarrow{-3} \mathrm{~B} ; \mathrm{O} \xrightarrow{+3} \mathrm{R} ; \mathrm{P} \xrightarrow{-3} \mathrm{M} ; \mathrm{L} \xrightarrow{+3} \mathrm{O} ; \mathrm{E} \xrightarrow{-3} \mathrm{~B}$
$\therefore$ SBRMOB

View full question & answer→

MCQ 111 Mark

The slope of line, whose equation is $5 x+6 y=7$ is

A
$\frac{6}{5}$
B
-5
C
$\frac{5}{6}$
✓
$-\frac{5}{6}$

Answer

Correct option: D.

$-\frac{5}{6}$

(d) $-\frac{5}{6}$
Explanation: equation is $5 x+6 y=7$
Slope $=\frac{\text { coefficient of } x}{\text { coefficient of } y}=\frac{-5}{6}$

View full question & answer→

MCQ 121 Mark

Let $\mathrm{A}=\{\mathrm{a}, \mathrm{b}, \mathrm{c}\}$, then the range of the relation $\mathrm{R}=\{(\mathrm{a}, \mathrm{b}),(\mathrm{a}, \mathrm{c}),(\mathrm{b}, \mathrm{c})\}$ defined on A is

✓
$\{b, c\}$
B
$\{c\}$
C
$\{\mathrm{a}, \mathrm{b}\}$
D
$\{\mathrm{a}, \mathrm{b}, \mathrm{c}\}$

Answer

Correct option: A.

$\{b, c\}$

(a) $\{b, c\}$
Explanation: Since the range is represented by the y - coordinate of the ordered pair ( $\mathrm{x}, \mathrm{y}$ ). Therefore, the range of the given relation is $\{b, c\}$.

View full question & answer→

MCQ 131 Mark

If $\log _{0.2} x=3$, then value of $x$ is

A
0.08
B
9
C
0.6
✓
0.008

Answer

Correct option: D.

0.008

(d) 0.008
Explanation: $\log _{0.2} \mathrm{x}=3$
$\log _{0.2}(0.2)^{3}=3$
$\log _{(0.2)} 0.008=3$
$\therefore \mathrm{x}=0.008$

View full question & answer→

MCQ 141 Mark

If $\mathrm{A}=\{-1,2,5,8\}, \mathrm{B}=(0,1,3,6,7\}$ and R be the relation "is one less than" from A to B , then R as a set of ordered pairs is

A
$\{(0,1),(2,3),(6,7)\}$
✓
$\{(-1,0),(2,3),(5,6)\}$
C
$\{(-1,0),(2,1),(8,7)\}$
D
$\{(1,2),(2,3),(5,6),(6,7),(7,8)\}\}$

Answer

Correct option: B.

$\{(-1,0),(2,3),(5,6)\}$

(b) $\{(-1,0),(2,3),(5,6)\}$
Explanation: $\{(-1,0),(2,3),(5,6)\}$

View full question & answer→

MCQ 151 Mark

Mean of the first $n$ terms of the A.P. $a+(a+d)+(a+2 d)+$ ______ is

✓
$a+\frac{(n-1) d}{2}$
B
$\frac{a+n d}{2}$
C
a + nd
D
$a+(n-1) d$

Answer

Correct option: A.

$a+\frac{(n-1) d}{2}$

(a) $a+\frac{(n-1) d}{2}$
Explanation: Mean $=\frac{\frac{n}{2}[2 a+(n-1) d]}{n}=\frac{[2 a+(n-1) d]}{2}=a+\frac{(n-1) d}{2}$

View full question & answer→

MCQ 161 Mark

Section 87 A refers to:

✓
tax rebate
B
investment in NSC
C
investment in ELSS
D
interest on a home loan

Answer

Correct option: A.

tax rebate

(a) tax rebate
Explanation: tax rebate

View full question & answer→

MCQ 171 Mark

The geometric mean and harmonic mean of two non-negative observations are 10 and 8 , respectively. Then, what is the arithmetic mean of the observations?

✓
12.5
B
9
C
4
D
25

Answer

Correct option: A.

12.5

(a) 12.5
Explanation: Given, geometric mean $(\mathrm{G})=10$ and harmonic mean $(\mathrm{H})=8$
Let A be the arithmetic mean, then $\mathrm{G}^{2}=\mathrm{AH}$
$\Rightarrow A=\frac{G^{2}}{H}$
$\Rightarrow A=\frac{(10)^{2}}{8}=\frac{100}{8}=12.5$

View full question & answer→

MCQ 181 Mark

The decimal equivalent of the binary number 10101 is

A
12
B
31
C
22
✓
21

Answer

Correct option: D.

21

(d) 21
Explanation: $10101=1 \times 2^{4}+0+1 \times 2^{2}+0+1 \times 2^{0}=16+4+1=21$

View full question & answer→

Generate Paper Free All Model Paper 9 topics

MCQ - Applied Maths STD 11 Science Questions - Vidyadip