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5 questions · timed · auto-graded

Question 11 Mark
Difference of two binary numbers 1011-101 = _________________
Answer
0110, because 
$\begin{array}{r}1 &0&1&1 \\ -\quad &1&0&1 \\ \hline 0&1&1& 0 \\ \hline\end{array}$
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Question 21 Mark
Sum of binary numbers 111 + 100 is _________________
Answer
1011, because 
$\begin{array}{r}1 &1&1 \\ +\quad 1&0&0 \\ \hline 10&1&1 \\ \hline\end{array}$
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Question 31 Mark
The input hexadecimal representation of 1110 is _________________
Answer
E, because
In hexadecimal number system 1110 = 15, which is represented by the alphabet E .
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Question 41 Mark
The octal equivalent of 1100101.001010 is _________________
Answer
145.12 , because
The octal equivalent is obtained by grouping the numbers into three bit from right to left before decimal and from left to right after the decimal place.
Here,
Image
Hence, 145.12 is the octal equivalent of the number.
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Question 51 Mark
If the decimal number is a fraction then its binary equivalent is obtained by _________________ the number continuously by 2 .
Answer
Multiplying, because
On multiplying the decimal continuously by 2 , the binary equivalent is obtained by the collection of the integer part. However, if it's binary equivalent is determined by dividing the number by 2 and collecting the remainders.
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Fill in the blanks. - Applied Maths STD 11 Science Questions - Vidyadip