The number of ways in which a team of 11 players can be selected from 22 players always including 2 of them and excluding 4 of them is
- A${ }^{16} C_{11}$
- B${ }^{16} C_5$
- ✓${ }^{16} C_9$
- D${ }^{20} C_9$
Answer: C.
View full solution →50 questions across 7 question groups — pick any mix to generate a Applied Maths paper with step-by-step answer keys.
MCQ
8 Q→022 Marks Questions
12 Q→033 Marks Question
7 Q→045 Marks Questions
7 Q→05Fill in the blanks.
8 Q→064 Marks Questions
6 Q→07Match the following.
2 Q→One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
Answer: C.
View full solution →Answer: A.
View full solution →Answer: B.
View full solution →Answer: B.
View full solution →Answer: B.
View full solution →| (a) In how many ways committee can be formed | (i) ${ }^{10} C_2 \times{ }^{19} C_3$ |
| (b) In how many ways a particular professor is included | (ii) ${ }^{10} C_2 \times{ }^{19} C_2$ |
| (c) In how many ways a particular lecturer is included | (iii) ${ }^{9} C_1 \times{ }^{20} C_3$ |
| (d) In how many ways a particular lecturer is excluded | (i) ${ }^{10} C_2 \times{ }^{20} C_3$ |
| $C _1$ | $C _2$ |
| (a) Boys and girls alternate | (i) $5!\times 6$ ! |
| (b) No two girls sit together | (ii) $10!-5! 6$ ! |
| (c) All the girls sit together | (iii) $(5!)^2+(5!)^2$ |
| (d) All the girls are never together | (iv) $5!\times 6$ ! |
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