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Question 14 Marks
Compute Cov(x, y) for the following pair of observations:
(15, 44), (20, 43), (25, 45), (30, 37), (40, 34), (50, 37)
Answer
Here,
$\bar{x}=\frac{15+20+25+30+40+50}{6}=\frac{180}{6}=30$
and
$\bar{y}=\frac{44+43+45+37+34+37}{6}=\frac{240}{6}=40$
Now, construct the following table:
$x$$x-\bar{x}$$y$$y-\bar{y}$$(x-\bar{x})(y-\bar{y})$
15-15444-60
20-10433-30
25-5455-25
30037-30
401034-6-60
502037-3-60
Total


-235

So, $\quad \begin{aligned} \operatorname{Cov}(x, y) & =\frac{1}{N} \Sigma(x-\bar{x})(y-\bar{y}) \\ & =\frac{1}{6}(-235)=-39.17\end{aligned}$
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Question 24 Marks
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Question 34 Marks
For the given set of data, calculate the percentile rank and quartile rank for observation 6.
5, 6, 6, 9, 11, 13, 15, 18, 20
Answer
The given data is already arranged in ascending order, so there is no need to arrange the data in ascending order.
Here, we can see that observation 6 comes under the repeated rank
So, here Y = 9 R = 2 and M = 2
(Here we choose the 6 which is at the farthest side. so, here we take 6 which is at 3sd rank, since, 6 is at 3 sd rank, therefore the ranks below to 6 are 2 i.e., the value of M = 2 )
We apply formula,
$P R=\left[\frac{M+(0.5 \times R)}{Y}\right] \times 100$
$\begin{array}{l}=\frac{2+(0.5 \times 2)}{9} \times 100 \\ =\frac{3}{9} \times 100=0.33 \times 10=33 \% 1 \end{array}$
Now, locating this percentile rank on quartile scale, we observe that, it lies between Q1 and Q2 Therefore, quartile ranking for score 6 is Q2
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4 Marks Questions - Applied Maths STD 11 Science Questions - Vidyadip