MCQ 11 Mark
Assertion $(A):$ The mean deviation about the mean for the data $4, 7, 8, 9, 10, 12, 13, 17$ is $3.$
Reason $(R):$ The mean deviation about the mean for the data $38, 70, 48, 40, 42, 55, 63, 46, 54, 44$ is $8.5.$
Reason $(R):$ The mean deviation about the mean for the data $38, 70, 48, 40, 42, 55, 63, 46, 54, 44$ is $8.5.$
- ABoth $A$ and $R$ are true and $R$ is the correct explanation of $A.$
- BBoth $A$ and $R$ are true but $R$ is not the correct explanation of $A.$
- ✓$A$ is true but $R$ is false.
- D$A$ is false but $R$ is true.
Answer
View full question & answer→Correct option: C.
$A$ is true but $R$ is false.
Assertion: Mean of the given series
$\overline{\bar{x}}=\frac{\text { Sum of terms }}{\text { Number of terms }}=\frac{\sum x_i}{n}$
$=\frac{4+7+8+9+10+12+13+17}{8}=10$
$\therefore$ Mean deviation about mean
$=\frac{\Sigma\left|x_i-\bar{x}\right|}{n}=\frac{24}{8}=3$
Reason Mean of the given series
$\bar{x}=\frac{\text { Sum of terms }}{\text { Number of terms }}=\frac{\sum x_i}{n}$
$=\frac{38+70+48+40+42+55}{+63+46+54+44}=50$
$\therefore$ Mean deviation about mean
$=\frac{\Sigma\left|x_i-\bar{x}\right|}{n}$
$=\frac{84}{10}=8.4$
Hence, Assertion is true and Reason is false.
$\overline{\bar{x}}=\frac{\text { Sum of terms }}{\text { Number of terms }}=\frac{\sum x_i}{n}$
$=\frac{4+7+8+9+10+12+13+17}{8}=10$
| $xi$ | $| x i -\bar{x}|$ |
| $4$ | $|4-10|=6$ |
| $7$ | $|7-10|=3$ |
| $8$ | $|8-10|=2$ |
| $9$ | $|9-10|=1$ |
| $10$ | $|10-10|=0$ |
| $12$ | $|12-10|=2$ |
| $13$ | $|13-10|=3$ |
| $17$ | $|17-10|=7$ |
| $\sum x_i=80$ | $\sum\left|x_i-\bar{x}\right|=24$ |
$=\frac{\Sigma\left|x_i-\bar{x}\right|}{n}=\frac{24}{8}=3$
Reason Mean of the given series
$\bar{x}=\frac{\text { Sum of terms }}{\text { Number of terms }}=\frac{\sum x_i}{n}$
$=\frac{38+70+48+40+42+55}{+63+46+54+44}=50$
$\therefore$ Mean deviation about mean
$=\frac{\Sigma\left|x_i-\bar{x}\right|}{n}$
$=\frac{84}{10}=8.4$
Hence, Assertion is true and Reason is false.