The probability of 53 Sundays in a leap year is :
- A$\frac{5}{7}$
- B$\frac{1}{7}$
- ✓$\frac{2}{7}$
- D$\frac{6}{7}$
Answer: C.
View full solution →48 questions across 7 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.
M.C.Q (1 Marks)
17 Q→02True False[1 Marks ]
6 Q→031 Marks Question
8 Q→042 Marks Questions
3 Q→05Fill In The Blanks[1 Marks ]
5 Q→065 Marks Questions
7 Q→07Match the following.
2 Q→One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
Answer: C.
View full solution →Answer: C.
View full solution →Answer: C.
View full solution →Answer: C.
View full solution →Answer: A.
View full solution →| Part (A) | Part (B) |
| 1. There are three red, four white and five blue balls in a bag. On taking out two balls from the bag, the probability of their being of different colours is | (a) $\frac{3}{7}$ |
| 2. 6 girls and 6 boys are sitting in a row. The probability of all girls sitting together is | (b) $\frac{47}{66}$ |
| 3. The probability of getting 1 on both dice when thrown together is | (c) $\frac{1}{132}$ |
| 4. Probability of 53 Fridays or 53 Saturdays in a leap year is | (d) $\frac{6}{216}$ |
| 5. Probability of obtaining same number on throwing 3 dice is | (e) $\frac{1}{36}$ |
| Part (A) | Part (B) |
| 1. Probability of obtaining three heads on tossing three coins | (a) $\frac{1}{6}$ |
| 2. Probability of obtaining at least two heads on tossing three coins | (b) $\frac{5}{6}$ |
| 3. Probability of getting a number less than 6 on throwing one dice | (c) $\frac{1}{8}$ |
| 4. Probability of getting a sum of 5 on throwing two dice | (d) $\frac{1}{9}$ |
| 5. Probability of getting a sum of 7 on throwing two dice | (e) $\frac{1}{2}$ |
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