Question types

Trigonometric Functions question types

76 questions across 6 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.

76
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6
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5
Question types
Sample Questions

Trigonometric Functions questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

If $\tan\theta=3$ and $\theta$ lies in third quadrant, then the value of $\sin\theta$ is:
  • A
    $\frac{1}{\sqrt{10}}$
  • B
    $-\frac{1}{\sqrt{10}}$
  • $\frac{-3}{\sqrt{10}}$
  • D
    $\frac{3}{\sqrt{10}}$

Answer: C.

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If A lies in the second quadrant and $3\tan\text{A}+4=0,$ then the value of $2\cot\text{A}-5\cos\text{A}+\sin\text{A}$ is equal to:
  • A
    $\frac{-53}{10}$
  • $\frac{23}{10}$
  • C
    $\frac{37}{10}$
  • D
    $\frac{7}{10}$

Answer: B.

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If $\tan(\text{A + B})=\text{p},\tan(\text{A}-\text{B})=\text{q},$ then show that $\tan2\text{A}=\frac{\text{p + q}}{1-\text{pq}}$
$\big[$Hint: Use $2\text{A}=(\text{A + B})+(\text{A}-\text{B})\big]$
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Q 163 Marks Question3 Marks
If $\text{a}\cos\theta+\text{b}\sin\theta=\text{m}$ and $\text{a}\sin\theta-\text{b}\cos\theta=\text{n},$ then show that $\text{a}^2+\text{b}^2=\text{m}^2+\text{n}^2.$
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Q 183 Marks Question3 Marks
Prove that $\cos\theta\cos\frac{\theta}{2}-\cos3\theta\cos\frac{9\theta}{2}=\sin7\theta\sin8\theta$
$\Big[$Hint: Express $\text{L.H.S.}=\frac{1}{2}\Big[2\cos\theta\cos\frac{\theta}{2}-2\cos3\theta\cos\frac{9\theta}{2}\Big]\Big]$
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Q 193 Marks Question3 Marks
If $\frac{\sin(\text{x+y})}{\sin(\text{x}-\text{y})}=\frac{\text{a+b}}{\text{a}-\text{b}},$ then show that $\frac{\tan\text{x}}{\tan\text{y}}=\frac{\text{a}}{\text{b}}.$
[Hint: Use Componendo and Dividendo]
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In a triangle ABC with $\angle\text{C}=90^\circ$ the equation whose roots are tan A and tan B is _______.
[Hint: $\text{A + B}=90^\circ\Rightarrow\tan\text{A}\tan\text{B}=1$ and $\tan\text{A}+\tan\text{B}=\frac{2}{\sin2\text{A}}$ ]
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In the following match each item given under the $\text{column}\  C_1$ to its correct answer given under the $\text{column}\  C_2$:
  $\text{column}\  C_1$   $\text{column}\  C_2$
$(a)$ $\sin(\text{x + y})\sin\text{x}-\text{y}$ $(i)$ $\cos^2\text{x}-\sin^2\text{y}$
$(b)$ $\cos(\text{x + y})\cos(\text{x}-\text{y})$ $(ii)$ $\frac{1-\tan\theta}{1+\tan\theta}$
$(c)$ $\cot\Big(\frac{\pi}{4}+\theta\Big)$ $(iii)$ $\frac{1+\tan\theta}{1-\tan\theta}$
$(d)$ $\tan\Big(\frac{\pi}{4}+\theta\Big)$ $(iv)$ $\sin^2\text{x}-\sin^2\text{y}$
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Find the value of the expression $\cos^4\frac{\pi}{8}+\cos^4\frac{3\pi}{8}+\cos^4\frac{5\pi}{8}+\cos^4\frac{7\pi}{8}$
[Hint: Simplify the expression to $2\Big(\cos^4\frac{\pi}{8}+\cos^4\frac{3\pi}{8}\Big)=2\Big[\Big(\cos^2\frac{\pi}{8}+\cos^2\frac{3\pi}8{}\Big)^2-2\cos^2\frac{\pi}{8}\cos^2\frac{3\pi}{8}\Big]$
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If $\text{x}=\sec\phi-\tan\phi$ and $\text{y}=\text{cosec}\phi+\cot\phi$ then show that $\text{xy}+\text{x}-\text{y}+1=0$
[Hint: Find xy + 1 and then show that x - y = -(xy + 1)]
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If $\cos\alpha+\cos\beta=0=\sin\alpha+\sin\beta,$ then prove that $\cos2\alpha+\cos2\beta=-2\cos(\alpha+\beta).$
$\big[$Hint: $(\cos\alpha+\cos\beta)^2-(\sin\alpha+\sin\beta)^2=0\big]$
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