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26 questions · timed · auto-graded

Question 13 Marks
Insert the appropriate sign of inequality:
$
\sqrt{3}(\sqrt{50}-\sqrt{32})
$ __________ $3 \sqrt{54}+2 \sqrt{24}$
Answer
$\sqrt{3}(\sqrt{50}-\sqrt{32})$ __________ < __________ $3 \sqrt{54}+2 \sqrt{24}$
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Question 23 Marks
Satyarth and Swarit are brothers, Satyarth owns a house which is worth a farmhouse which is worth ₹ 2.75 crores. But Satyarth has a debt of their properties then which of the following statement(s) holds true to mathematically: ₹ 3 crores and Swarit owns ₹ 55 lakhs, if they both sell represent the above data
a) Satyarth's net worth is more than Swarit's net worth.
b) Swarit's net worth is more than Satyarth's net worth.
c) 2.55 < 2.75
Answer
b, c are true
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Question 33 Marks
Arun started a business investing ₹ 38000. After 5 months Bakul joined him with a capital of ₹ 55000. At the end of the year the total profit was ₹ 22000. What is the approximate Activate difference between the shares of Arun and Bakul?
Answer
1857
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Question 43 Marks
Rahul got ₹ 5000 as his share out of the total profit of ₹ 9000. Ramesh had invested ₹ 3000 for 6 months, while Rahul invested for the whole year. Find the amount invested by Rahul.
Answer
1875
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Question 53 Marks
A,B and C enter into a partnership. B contributes 1/3 of the capital, while A contributes as much as B and C together contribute. Find the ratio of their capitals.
Answer
$3: 2: 1$
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Question 63 Marks
In a 900 metres race, A gives B a start of 150 metres and defeats him by 50 seconds. If the speed of A is 4.5m/sec then find the speed of B.
Answer
$3 m / sec$
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Question 73 Marks
In a 1000 metres race, A can give a start of 100 metres to B and a start of 280 metres to C. In the same race, how much start can B give to C?
Answer
200 meters
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Question 83 Marks
In a 1000 metres race, A defeats B by 300 metres and B defeats C by 200meters. In the same race by how many metres will A defeat C?
Answer
440 meters
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Question 93 Marks
Two pipes A and B can fill a tank in 24 minutes and 32 minutes respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 minutes?
Answer
8 minutes
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Question 103 Marks
A cistern can be filled by an inlet pipe in 20 hours and can be emptied by an outlet pipe in 25 hours. Both the pipes are opened. After 10 hours, the outlet pipe is closed, find the total time taken to fill the tank.
Answer
28 hours
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Question 113 Marks
A man can row $71 / 2 km / h$ in still water. If in a river running at 1.5 km an hour, it takes him 50 minutes to row to a place and back ,how far off is the place?
Answer
3 km
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Question 123 Marks
A container has $50 /$ of juice in it. $5 /$ of juice is taken out and is replaced by $5 /$ of water. This process is repeated 4 more times. What is the amount of juice in the container after final replacement?
Answer
29.5 litre
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Question 133 Marks
A shopkeeper has 1 quintal of wheat, part of which she sells at $18 \%$ gain and the rest at $28 \%$ gain. In total she gains $24 \%$. Find the quantity of wheat sold at $18 \%$ and $28 \%$.
Answer
400 kg , 600 k
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Question 163 Marks
Find the positive integers less than 50 forming the equivalence class 4 for modulo 6
Answer
4, 10, 16, 22, 28, 34, 40,
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Question 203 Marks
Find the remainder when (127 x137 x23 x50 x235x15) is divided by 7.
Answer
As we know that $((A \times B) \bmod C=(A \bmod C \times B \bmod C) \bmod C) \ldots$. (i)
Therefore, for calculating ( $127 \times 137 \times 23 \times 50 \times 235 \times 15) \bmod 7$, let us find
$127 \bmod 7=1$
$137 \bmod 7=4$
$23 \bmod 7=2$
$50 \bmod 7=1$
$235 \bmod 7=4$
$15 \bmod 7=1$
using equation (i) repeatedly we have:
$(127 \times 137 \times 23 \times 50 \times 235 \times 15) \bmod 7=(1 \times 4 \times 2 \times 1 \times 4 \times 1) \bmod 7$ $=32(\bmod 7)=4$
Hence remainder is 4
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Question 213 Marks
Three friends A,B and C enter into a partnership to run a café business. A puts in 5000 per month for the whole year, B contributes 3000 per month at first and increases his contribution to 4500 at the end of 4 months, while C puts in at first 4000 per month and withdraws 1000 at the end of nine months. How should they divide a profit of 10200 at the of 10200 at the year?
Answer
A's equivalent capital for 1 month = ₹ (5000x12)=60000
B's equivalent capital for 1 month = ₹ (3000x4 + 4500x8)= 48000
C's equivalent capital for 1 month = ₹ (4000x9+3000x3)= 45000
Ratio of the capitals is 60000:48000:45000 or 20:16:15
A's share ₹$\frac{10200 \times 20}{51}=$= ₹ 4000
B's share ₹$\frac{10200 \times 16}{51}=$= ₹ 3200
C's share ₹$\frac{10200 \times 15}{51}=$= ₹ 3000
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Question 223 Marks
A cistern can be filled by two pipes A and B in 12 minutes and 15 minutes respectively. Another tap C can empty the full tank in 20 minutes. If the tap C is opened 5 minutes after the pipes A and B are opened, find when the cistern becomes full?
Answer
Cistern filled by $A$ and $B$ in 5 minutes $=5\left(\frac{1}{12}+\frac{1}{15}\right)=\frac{3}{4}$ Unfilled part of the tank $=\frac{1}{4}$
Portion of cistern filled by $A, B$ and $C$ in 1 minute $=\frac{1}{12}+\frac{1}{15}-\frac{1}{20}=\frac{1}{10}$
So, $\frac{1}{4}$ of the tank will be filled in $=\frac{1}{4} \times 10=2 mins 30$ secs
Total time taken to fill the tank $=5+2$ mins 30 secs $=7$ mins 30 secs
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Question 233 Marks
Two pipes can fill a cistern in 8 and 12 hours respectively. The pipes are opened simultaneously and it takes 12 minutes more to fill the cistern due to leakage. If the cistern is full, what will be the time taken by the leakage to empty it?
Answer
Portion of cistern filled (work done) by both the pipes in 1 hour $=\frac{1}{8}+\frac{1}{12}=\frac{5}{24}$
Time taken by both the pipes to fill the tank $=\frac{24}{5} hr =4 hrs 48$ minutes
Time taken to fill the tank due to leakage $=4 hrs 48$ minutes +12 minutes $=5 hrs$
Net work done by the pipes and the leakage in $1 hr =\frac{1}{5}$
Work done by leakage in $1 hr =\frac{5}{24}-\frac{1}{5}=\frac{1}{120}$
Time taken by leakage to empty the tank $=120 hrs$.
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Question 243 Marks
A container contains 40 litre milk. From this container 4 litre milk was taken out and replaced with water. This process was repeated further two more times. How much milk is there in the container now?
Answer
Total milk in container $=40 l$
Milk taken out $=4 l$
No. of times process repeated $=3$
Milk contained by the container now $=x\left(1-\frac{y}{x}\right)^n$ unit
where $x$ is total quantity, $y$ is quantity removed, $n$ is no. of times operation repeated.
$
\begin{array}{l}
=40\left(1-\frac{4}{40}\right)^3 \\
=40\left(\frac{9}{10} \times \frac{9}{10} \times \frac{9}{10}\right) \\
=40 \times \frac{729}{1000} \\
=29.16 l
\end{array}
$
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Question 253 Marks
A retailer has 250 kg of rice, a part of which he sells at 10% profit. The remaining quantity of rice is of low quality and he sold it at 5% loss. Overall he made a profit of 7%. Find the quantity of rice sold at 5% loss.
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Question 263 Marks
Find all the positive integers less than 30 forming the equivalence class of 5 for modulo 7.
Answer
The smallest positive integer divisible by 7 is 7.
Therefore, 5 mod 7 = 5
7 + 5 = 12
So, 12 mod 7 = 5
19 mod 7 = 5
26mod 7 = 5
Hence, positive integers less than 30 forming the equivalence class 5 for modulo 7 are 5, 12, 19,
and 26.
Therefore [5] = { 5, 12, 19, 26}
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3 Marks Question - Applied Maths STD 12 Science Questions - Vidyadip