Question 14 Marks
Answer
View full question & answer→1. (D) $x \in(5, \infty)$
Explanation: The given figure represents all value of x greater than 5 excluding 5 on the real number line.
So, $x \in(5, \infty)$
2. (B) $x \geq 4$
Explanation: $\frac{-3}{4} x \leq-3$
$x \geq 4 \quad \Rightarrow \quad x \geq-3 \times \frac{-4}{3}$
3. (C) No Solution
Explanation: We have,
$4 x+3 \geq 2 x+17$
$\Rightarrow 4 x-2 x \geq 17-3$
$\Rightarrow 2 x \geq 14$
$\Rightarrow x \geq \frac{14}{2}$
$\Rightarrow x \geq 7$
Also, we have $3x - 5 < - 2$
$\Rightarrow 3x < - 2 + 5$
$\Rightarrow 3x < 3$
$\Rightarrow x < 1$
On combining Eqs. (i) and (ii), we see that solution is not possible because nothing is common between these two solutions,
(i.e., $x<1, x \geq 7$).
4. (A) $x \in(-\infty,-2]$
Explanation: The given figure represent all real values of x less than and equal to $-2.$
So $x \in(-\infty,-2]$.
Explanation: The given figure represents all value of x greater than 5 excluding 5 on the real number line.
So, $x \in(5, \infty)$
2. (B) $x \geq 4$
Explanation: $\frac{-3}{4} x \leq-3$
$x \geq 4 \quad \Rightarrow \quad x \geq-3 \times \frac{-4}{3}$
3. (C) No Solution
Explanation: We have,
$4 x+3 \geq 2 x+17$
$\Rightarrow 4 x-2 x \geq 17-3$
$\Rightarrow 2 x \geq 14$
$\Rightarrow x \geq \frac{14}{2}$
$\Rightarrow x \geq 7$
Also, we have $3x - 5 < - 2$
$\Rightarrow 3x < - 2 + 5$
$\Rightarrow 3x < 3$
$\Rightarrow x < 1$
On combining Eqs. (i) and (ii), we see that solution is not possible because nothing is common between these two solutions,
(i.e., $x<1, x \geq 7$).
4. (A) $x \in(-\infty,-2]$
Explanation: The given figure represent all real values of x less than and equal to $-2.$
So $x \in(-\infty,-2]$.




