M.C.Q (1 Marks)

MCQ 11 Mark

Identify the major product $\mathrm{C}$ formed in the following reaction sequence:

$Image$

A
butylamine
B
butanamide
C
$\alpha$-bromobutanoic acid
✓
propylamine

Answer

Correct option: D.

propylamine

d
$Image$

- Step$-l$ is $\mathrm{S}_{\mathrm{N}}$ reaction with $\stackrel{\ominus}{\mathrm{C}} \mathrm{N}$ nucleophile.

- Step$-Il$ will give amide.

- Step$-III$ is Hoffmann bromamide degradation reaction.

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MCQ 21 Mark

Given below are two statements:

Statement $I$ : Aniline does not undergo Friedel-Crafts alkylation reaction.

Statement $II$ : Aniline cannot be prepared through Gabriel synthesis.

In the light of the above statements, choose the correct answer from the options given below:

A
Both Statement $I$ and Statement $II$ are false
B
Statement $I$ is correct but Statement $II$ is false
C
Statement $I$ is incorrect but Statement $II$ is true
✓
Both statement $I$ and Statement $II$ are true

Answer

Correct option: D.

Both statement $I$ and Statement $II$ are true

d
- Aniline does not undergo Friedel-Crafts alkylation reaction due to salt formation with aluminium chloride, the Lewis acid, which is used as a catalyst.

- Aniline (aromatic primary amine) cannot be prepared by Gabriel phthalimide synthesis because aryl halides do not undergo nucleophilic substitution with anion formed by phthalimide.

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MCQ 31 Mark

Which of the following reactions will NOT give primary amine as the product?

A
$CH_3CN \xrightarrow[(ii) H _3 O ^{\oplus}]{(i) LiAlH_4}$ product
B
$CH_3CONH_2 \overset{Br_2/KOH}{\rightarrow}$ product
C
$CH_3CONH_2 \xrightarrow[(ii) H _3 O ^{\oplus}]{(i) LiAlH_4}$ product
✓
$CH_3NC \xrightarrow[(ii) H _3 O ^{\oplus}]{(i) LiAlH_4}$ product

Answer

Correct option: D.

$CH_3NC \xrightarrow[(ii) H _3 O ^{\oplus}]{(i) LiAlH_4}$ product

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MCQ 41 Mark

Given below are two statements:

Statement $I:$ Primary aliphatic amines react with $HNO _{2}$ to give unstable diazonium salts.

Statement $II:$ Primary aromatic amines react with $HNO _{2}$ to form diazonium salts which are stable even above $300 \,K$.

In the light of the above statements, choose the most appropriate answer from the options given below:

A
Both Statement $I$ and Statement $II$ are incorrect.
✓
Statement $I$ is correct but Statement $II$ is incorrect.
C
Statement $I$ is incorrect but Statement $II$ is correct.
D
Both Statement $I$ and Statement $II$ are correct.

Answer

Correct option: B.

Statement $I$ is correct but Statement $II$ is incorrect.

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MCQ 51 Mark

The product formed from the following reaction sequence is ?

Answer

Correct option: C.

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MCQ 61 Mark

Identify the compound that will react with Hinsberg's reagent to give a solid which dissolves in alkali.

Answer

Correct option: C.

c
$1^{\circ}$ amine reacts with hinsberg reagent to give ppt. that is soluble in alkali.

$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{NH}_{2}$

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MCQ 71 Mark

Reaction of propanamide with ethanolic sodium hydroxide and bromine will give

A
Aniline
✓
Ethylamine
C
Methylamine
D
Propylamine

Answer

Correct option: B.

Ethylamine

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MCQ 81 Mark

Which of the following amine will give the carbylamine test$?$

Answer

Correct option: B.

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MCQ 91 Mark

The correct order of the basic strength of methyl substituted amines in aqueous solution is

✓
$\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}>\mathrm{CH}_{3} \mathrm{NH}_{2}>\left(\mathrm{CH}_{3}\right)_{3} \mathrm{N} $
B
$\left(\mathrm{CH}_{3}\right)_{3} \mathrm{N}>\mathrm{CH}_{3} \mathrm{NH}_{2}>\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}$
C
$\left(\mathrm{CH}_{3}\right)_{3} \mathrm{N}>\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH} > \mathrm{CH}_{3} \mathrm{NH}_{2}$
D
$\mathrm{CH}_{3} \mathrm{NH}_{2}>\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}>\left(\mathrm{CH}_{3}\right)_{3} \mathrm{N}$

Answer

Correct option: A.

$\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}>\mathrm{CH}_{3} \mathrm{NH}_{2}>\left(\mathrm{CH}_{3}\right)_{3} \mathrm{N} $

a
The order of basic strength in case of methyl substituted amines and ethyl substituted amines in aqueous solution is as follows:

$\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{NH}>\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{3} \mathrm{N}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}>\mathrm{NH}_{3}$

$\left(\mathrm{CH}_{3}\right)_{2}\mathrm{NH}>\mathrm{CH}_{3} \mathrm{NH}_{2}>\left(\mathrm{CH}_{3}\right)_{3} \mathrm{N}>\mathrm{NH}_{3}$

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MCQ 101 Mark

The amine that reacts will Hinsberg's reagent to give an alkali insoluble product is

✓
$\begin{array}{*{20}{c}}
{C{H_3} - CH - NH - CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,} \\
{\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
B
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2} - C{H_3}} \\
| \\
{C{H_3} - C{H_2} - N - C{H_2} - C{H_3}}
\end{array}$
C
$\begin{array}{*{20}{c}}
{N{H_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - C{H_2} - C{H_2} - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
D
$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - CH - N{H_2}} \\
{|\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,} \\
{C{H_3}\,\,C{H_3}}
\end{array}$

Answer

Correct option: A.

$\begin{array}{*{20}{c}}
{C{H_3} - CH - NH - CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,} \\
{\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$

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MCQ 111 Mark

Nitration of aniline in strong acidic medium also gives m-nitroaniline because

A
In spite of substituents nitro group always goes to only $m-$position
B
In electrophilic substitution reactions amino group is meta directive.
C
In absence of substituents nitro group always goes to m-position
✓
In acidic (strong) medium aniline is present as anilinium ion

Answer

Correct option: D.

In acidic (strong) medium aniline is present as anilinium ion

d
In acidic medium aniline is protonated to form anilinium ion which is metadirecting.

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MCQ 121 Mark

Which of the following reactions is appropriate for converting acetamide to methanamine?

✓
Hoffmann hypobromamide reaction
B
Stephen's reaction
C
Gabriel phthalimide synthesis
D
Carbylamine reaction

Answer

Correct option: A.

Hoffmann hypobromamide reaction

a
$\begin{matrix}
C{{H}_{3}}-C-N{{H}_{2}} \\
|| \\
O \\
\end{matrix}$ $\xrightarrow{B{{r}_{2}}\,/\,4KOH}$ $C{{H}_{3}}-N{{H}_{2}}\,+\,2KBr\,+\,{{K}_{2}}C{{O}_{3}}$

This reactlon is known as hoffmann hypobromamide reaction.

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MCQ 131 Mark

The correct increasing order of basic strength for the following compounds is

A
$III < I < II$
B
$III < II < I$
✓
$II < I < III$
D
$II < III < I$

Answer

Correct option: C.

$II < I < III$

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MCQ 141 Mark

The reaction:

$ArN _{2} Cl \overset{Cu / HCl}{\rightarrow} ArCl + N _{2}$ is known as

A
Sandmeyers reaction
B
Finkelstein reaction
✓
Gattermann reaction
D
Balz Schiemann reaction

Answer

Correct option: C.

Gattermann reaction

c
Getterman process

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MCQ 151 Mark

The product $(P)$ of the following reaction

Answer

Correct option: C.

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MCQ 161 Mark

Match Column$-I$ with Column$-II:$

A
$A-P; B-Q; C-R$
B
$A - Q ; B - R ; C - P$
✓
$A - R ; B - P ; C - Q$
D
$A-R; B-Q; C-P$

Answer

Correct option: C.

$A - R ; B - P ; C - Q$

c
$A - R ; B - P ; C - Q$

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MCQ 171 Mark

The product formed by the reaction of an aldehyde with a primary amine is

A
carboxylic acid
B
aromatic acid
✓
Schiff's base
D
ketone

Answer

Correct option: C.

Schiff's base

c
Aldehyde + Primary amines $\rightarrow$ Schiff base

Schiff bases can be synthesized from an aliphatic or aromatic amine and a carbonyl compounds by nucleophilic addition-elimination reaction

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MCQ 181 Mark

Which one of the following nitro-compounds does not react with nitrous acid ?

Answer

Correct option: C.

c
$1^{o}$ nitro compound,

$2^{o}$ nitro compound react with $\mathrm{HNO}_{2}$ acid

but $3^{o}$ nitro compound does not react with nitrous acid.

$(i)$ ${\mkern 1mu} \mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_2}} \\
{|\,\,}
\end{array}} \\
{C{H_3} - C - CH - N{O_2}} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}}\limits_{{1^o}\,\,nitro} $ $\xrightarrow{{HN{O_2}}}$ $\begin{matrix}
\,\,\,\,\,\,\,\,\,\begin{matrix}
\,\,\,\,\,\,C{{H}_{3}} \\
| \\
\end{matrix} \\
C{{H}_{3}}-C-C-N{{O}_{2}} \\
\,||\,\,\,\,\,\,\,\,\,|\,\, \\
\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,N=O \\
\end{matrix}$

$(ii)$ $\mathop {C{H_3} - C{H_2} - C{H_2} - N{O_2}}\limits_{{1^o}\,nitro} $ $\xrightarrow{{HO - N = O}}$ $\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - C - N{O_2}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,N - OH}
\end{array}$

$(iii)$ $\mathop {\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - N{O_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\,}\limits_{{1^o}\,\,nitro} $ $\xrightarrow{{HO - N = O}}$ $\begin{matrix}
C{{H}_{3}}-CH-C-N{{O}_{2}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,|| \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,\,\,N-OH \\
\end{matrix}$

$3^o$ nitro $\xrightarrow{HN{{O}_{2}}}$ No reaction.

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MCQ 191 Mark

The correct statement regarding the basicity of arylamines is

A
arylamines are generally more basic than alkylamines because of aryl group
B
arylamines are generally more basic than alkylamines, because the nitrogen atom in arylamines is $sp-$hybridised
✓
arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalised by interaction with the aromatic ring $\pi -$electron system
D
arylamines are generally more basic than alkylamines because the nitrogen lone-pair electrons are not delocalised by interaction with the aromatic ring $\pi -$electron system.

Answer

Correct option: C.

arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalised by interaction with the aromatic ring $\pi -$electron system

c
Delocalized lone pair of nitrogen less basic

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MCQ 201 Mark

A given nitrogen-containing aromatic compound $'A'$ reacts with $Sn/HCl,$ followed by $HNO_2$ to give an unstable compound $'B'$. $ 'B',$ on treatment with phenol, forms a beautiful coloured compound $'C'$ with the molecular formula $C_{12}H_{10}N_2O.$ The structure of compound $'A'$ is

Answer

Correct option: B.

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MCQ 211 Mark

The electrolytic reduction of nitro benzene in strongly acidic medium produces

A
azobenzene
B
aniline
✓
$p-$aminophenol
D
azoxybenzene

Answer

Correct option: C.

$p-$aminophenol

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MCQ 221 Mark

Method by which aniline cannot be prepared is

A
degradation of benzamide with bromine in alkaline solution
B
reduction of nitrobenzene with $H_2/Pd$ in ethanol
✓
potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous $NaOH$ solution
D
hydrolysis of phenylisocyanide with acidic solution.

Answer

Correct option: C.

potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous $NaOH$ solution

c
due to resonance $C-Cl$ bond acquires double bond character.

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MCQ 231 Mark

In the following reaction, the product $(A)$ is

Answer

Correct option: D.

d
The above reaction is a coupling reaction of aniline with diazonlum salt to give azo benzene compound. This coupling reaction takes place at the para-position to $- NH_2$ group of benzene. This reaction act as electrophilic substitution reaction of aniline.

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MCQ 241 Mark

Which of the following will be most stable diazonium salt $RN_2^+X^-$ ?

A
$CH_3N_2^+X^-$
✓
$C_6H_5N_2^+X^-$
C
$CH_3CH_2N_2^+X^-$
D
$C_6H_5CH_2N_2^+X^-$

Answer

Correct option: B.

$C_6H_5N_2^+X^-$

b
Diazonium salt containing aryl group directly linked to the nitrogen atom is most stable due to resonance stabilisation between the benzene nucleus and $N-$atom. Diazonium ion act as a electrophile. [Resonance structure of benzene diazonium ion]

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MCQ 251 Mark

Nitrobenzene on reaction with conc. $HNO_3/H_2SO_4$ at $80-100\,^o C$ forms which one of the following products ?

A
$1, 4-$Dinitrobenzene
B
$1, 2, 4-$Trinitrobenzene
C
$1, 2-$Dinitrobenzene
✓
$1, {3-}$Dinitrobenzene

Answer

Correct option: D.

$1, {3-}$Dinitrobenzene

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MCQ 261 Mark

In the reaction $A$ is

✓
$H_3PO_2$ and $H_2O$
B
$H^+/H_2O$
C
$HgSO_4/H_2SO_4$
D
$Cu_2Cl_2$

Answer

Correct option: A.

$H_3PO_2$ and $H_2O$

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MCQ 271 Mark

On hydrolysis of a "compound", two compounds are obtained. One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollens reagent and Fehling's solution. The "compound" is

✓
$CH_3CH_2CH_2NC$
B
$CH_3CH_2CH_2CN$
C
$CH_3CH_2CH_2ON=O$
D
$CH_3CH_2CH_2CON(CH_3)_2$

Answer

Correct option: A.

$CH_3CH_2CH_2NC$

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MCQ 281 Mark

Some reactions of amines are given. Which one is not correct ?

✓
B
$CH_3CH_2NH_2 + HNO_2 \rightarrow CH_3CH_2OH + N_2$
C
$CH_3NH_2 + C_6H_5SO_2Cl \rightarrow CH_3NHSO_2C_6H_5$
D
$(CH_3)_2NH + NaNO_2 + HCl \rightarrow (CH_3)_2N-N=O$

Answer

Correct option: A.

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MCQ 291 Mark

${(RCO)_2}NH$ is

A
Primary amine
B
Secondary amine
✓
Secondary amide
D
Tertiary amide

Answer

Correct option: C.

Secondary amide

c
(c)$\mathop {R - CON{H_2}}\limits_{{\rm{Primary amide}}} $ $\mathop {{{(RCO)}_2}NH}\limits_{{\rm{Secondary amide}}} $

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MCQ 301 Mark

Which of the following is ${1^o}$ amine

✓
Ethylene diamine
B
Dimethyl amine
C
Trimethyl amine
D
$N-$methyl aniline

Answer

Correct option: A.

Ethylene diamine

a
in ethylene diamine here both amine are bond with different methyl group so this is $1^{\circ}$ amine

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MCQ 311 Mark

A secondary amine is

A
An organic compound with two $ - N{H_2}$ groups
B
A compound with two carbon atoms and an $ - N{H_2}$ group
C
A compound with an $ - N{H_2}$ group on the carbon atom in number $2$ position
✓
A compound in which two of the hydrogens of $N{H_3}$ have been replaced by organic groups

Answer

Correct option: D.

A compound in which two of the hydrogens of $N{H_3}$ have been replaced by organic groups

d
It’s obvious.

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MCQ 321 Mark

The structural formula of methyl aminomethane is

A
${(C{H_3})_2}CHN{H_2}$
B
${(C{H_3})_3}N$
✓
${(C{H_3})_2}NH$
D
$C{H_3}N{H_2}$

Answer

Correct option: C.

${(C{H_3})_2}NH$

c
structure of amino methane $CH _3- CH _2- NHCH _3$

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MCQ 331 Mark

Triaminobenzene is a

A
${2^o}$ amine
B
${3^o}$ amine
✓
${1^o}$ amine
D
Quarternary salt

Answer

Correct option: C.

${1^o}$ amine

c
(c)

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MCQ 341 Mark

Aniline is usually purified by

✓
Steam distillation
B
Simple distillation
C
Vacuum distillation
D
Extraction with a solvent

Answer

Correct option: A.

Steam distillation

a
Aniline is purified by steam distillation. The temperature required for the simple distillation of aniline is too high. It decomposes at this temperature. Steam distillation occurs at lower temperature.

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MCQ 351 Mark

The Hinsberg's method is used for

A
Preparation of primary amines
B
Preparation of secondary amines
C
Preparation of tertiary amines
✓
Separation of amine mixtures

Answer

Correct option: D.

Separation of amine mixtures

d
It’s obvious.

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MCQ 361 Mark

The diazonium salts are the reaction products in presence of excess of mineral acid with nitrous acid and

A
Primary aliphatic amine
B
Secondary aromatic amine
✓
Primary aromatic amine
D
Tertiary aliphatic amine

Answer

Correct option: C.

Primary aromatic amine

c
The diazonium salts are the reaction product in presence of excess of mineral acid with nitrous acid and primary aromatic amine

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MCQ 371 Mark

The amine which can react with ${C_6}{H_5} - S{O_2} - Cl$ to form a product insoluble in alkali shall be

A
Primary amine
✓
Secondary amine
C
Tertiary amine
D
Both primary and secondary amines

Answer

Correct option: B.

Secondary amine

b
(b) ${C_6}{H_5}S{O_2}Cl$ is called Hinsberg’s reagent they react with sec amine to form a product in soluble in alkalies. This reaction used to separate ${1^o}$, ${2^o}$ and ${3^o}$ amine from their mixture.

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MCQ 381 Mark

A mixture of benzene and aniline can be separated by

A
Hot water
✓
dil. $HCl$
C
dil. $NaOH$
D
Alcohol

Answer

Correct option: B.

dil. $HCl$

b
(b) A mixture of benzene and aniline can be separated by dil. $HCl$.

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MCQ 391 Mark

Pure aniline is a

A
Colourless solid
B
Brown coloured solid
✓
Colourless liquid
D
Brown coloured liquid

Answer

Correct option: C.

Colourless liquid

c
Pure aniline is colurless liquid.But it gets easily oxidized by air.Hence, it develops color.

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MCQ 401 Mark

Which has a pyramidal structure

✓
Trimethylamine
B
Methanol
C
Acetylene
D
Water

Answer

Correct option: A.

Trimethylamine

a
Trimethylamine has a pyramidal shape. Center atom is $sp^3$ hybridized with three bond pairs and one lone pair.

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MCQ 411 Mark

Amines behave as

A
Lewis acids
✓
Lewis bases
C
Aprotic acids
D
Amphoteric compounds

Answer

Correct option: B.

Lewis bases

b
(b) In amines nitrogen has a lone pair of ${e^ - }$. It can donate a election pair. So amines behaves as a lewis base.

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MCQ 421 Mark

In amines, the hybridisation state of $N$ is

A
$sp$
B
$s{p^2}$
✓
$s{p^3}$
D
$s{p^2}d$

Answer

Correct option: C.

$s{p^3}$

c
(c) It is similar that of $N{H_3}$ except $H-$ is replaced by $-R$ group.

$\because \mathop {N{H_3}}\limits^{ \cdot \,\, \cdot \,\,\,\,\,\,} \to \frac{{5 + 3}}{2} \Rightarrow 4 \Rightarrow s{p^3}$.

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MCQ 431 Mark

The structural formula of an amino acid, isoleucine is :-

A
$\begin{array}{*{20}{c}}
{N{H_2}} \\
{|\,\,\,\,\,} \\
{C{H_3} - CH \cdot COOH}
\end{array}$
B
✓
D

Answer

Correct option: C.

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MCQ 441 Mark

Which of following statement is correct ?

✓
Hinsberg reagent can be use to seperate $1^o,\, 2^o$ and $3^o$ amine
B
Hinsberg reagent can not be use to distinguish $1^o,\, 2^o$ and $3^o$ amine
C
Volatile nature of isomeric amine $1^o > 2^o > 3^o$
D
Primary amine and secondary amine can not be distinguished by liebermann nitroso test

Answer

Correct option: A.

Hinsberg reagent can be use to seperate $1^o,\, 2^o$ and $3^o$ amine

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MCQ 451 Mark

Which of following can be use to distinguish primary, secondary and tertiary amine ?

A
Hinsberg reagent
B
$HNO_2$
C
Carbyl amine test
✓
$A$ and $B$ both

Answer

Correct option: D.

$A$ and $B$ both

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MCQ 461 Mark

Among the isomeric amines select the one with the lowest boiling point.

Answer

Correct option: C.

c
does not participate in $H$- bonding so has least $B.P.$

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MCQ 471 Mark

The structure of products $E -H,$ respectively are

✓
$3, 2, 6, 7$
B
$4, 5, 6, 1$
C
$3, 4, 5, 2$
D
$3, 2, 4, 5$

Answer

Correct option: A.

$3, 2, 6, 7$

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MCQ 481 Mark

Which is not primary amine ?

A
Secondary butyl amine
B
Tertiary butyl amine
✓
$N-$ methyl ethanamine
D
All of these

Answer

Correct option: C.

$N-$ methyl ethanamine

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MCQ 491 Mark

Which of following statement is correct ?

✓
Hinsberg reagent can be use to seperate $1^o, 2^o$ and $3^o$ amine.
B
Hinsberg reagent can not be use to distinguish $1^o, 2^o$ and $3^o$ amine
C
Volatile nature of isomeric amine $1^o > 2^o > 3^o$
D
Primary amine and secondary amine can not be distinguished by liebermann nitroso test

Answer

Correct option: A.

Hinsberg reagent can be use to seperate $1^o, 2^o$ and $3^o$ amine.

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MCQ 501 Mark

Primary and secondary amines can be distinguished by

A
Hoffmann's mustard oil reaction
B
carbylamine reaction
C
Hinsberg reagent
✓
All

Answer

Correct option: D.

All

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Chemistry M.C.Q (1 Marks)

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