A wire of length ' $r$ ' and resistance $100 \Omega$ is divided into $10$ equal parts. The first $5$ parts are connected in series while the next $5$ parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:
- ✓$52 \Omega$
- B$55 \Omega$
- C$60 \Omega$
- D$26 \Omega$
Answer: A.
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