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43 questions · timed · auto-graded

Question 12 Marks
What is called scattering of light?
Answer
When light strikes with atoms or molecules or particles having size of the order of wavelength of light, first it gets absorbed and then these particles immediately reemits light in different directions with different amounts. Such phenomenon is called "Scattering of light".
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Question 22 Marks
Though planets are closer to us compared to stars, they do not twinkle. Why?
Answer
As compared to stars, planets are much closer to us. That is why they appear bigger.
Light coming from planet is like a beam of light, coming from cluster of point like sources of light (a collection of large no. of point sized sources of light). Here resultant variation in the amount of light entering our eyes from all the individual and independent pointlike sources comes out to be zero on average, Hence twinkling effects of individual sources are getting nullified. That is why planets do not twinkle.
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Question 32 Marks
What is caused by damage or malfunction of any part of our visual system ?
Answer
Damage or malfunction of any part of our visual system causes visual impairment (i.e. loss of sight partly or completely, unclear vision, defect of vision)
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Question 42 Marks
Mention in brief about "cataract" and its remedy
Answer
Crystalline lens of some people becomes milky and cloudy at old age. Such condition of eye is called "cataract."
→ Person having cataract, may lose vision partially or completely.
→ Nowadays it is quite possible to replace such lens by an artificial lens through "cataract surgery" to restore the vision.
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Question 52 Marks
Define refraction of light.
Answer
  • The change in the direction of light, at the boundary separating the two media, when it passes from one transparent medium to another obliquely, is called refraction of light.
OR
  • Bending of light, at the boundary separating the two media, when it travels from one transparent medium to another obliquely, is called refraction of light.
OR
  • When a ray of light travels obliquely from one transparent medium to another, its speed changes.
  • Therefore at the boundary separating the two media, there occurs a change in its direction of propagation.
  • This phenomenon is called refraction of light.
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Question 62 Marks
What is refraction of light?
Answer
  • The change in the direction of light, at the boundary separating the two media, when it passes from one transparent medium to another obliquely, is called refraction of light.
OR
  • Bending of light, at the boundary separating the two media, when it travels from one transparent medium to another obliquely, is called refraction of light.
OR
  • When a ray of light travels obliquely from one transparent medium to another, its speed changes.
  • Therefore at the boundary separating the two media, there occurs a change in its direction of propagation.
  • This phenomenon is called refraction of light.
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Question 72 Marks
Give the scientific reason : A watch repairer uses a convex lens.
Answer
  • If an object is kept between optical centre $O$ and principal focus $F$ of a convex lens, we get a virtual, erect and enlarged image of the object on the same side of the object, beyond the distance $2f$ from the lens.
  • Thus, by keeping a watch between the lens and its principal focus, the watch repairer can see minute parts of the watch clearly, so that repairing becomes easy.
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Question 82 Marks
What is the lens formula? State the lens formula for a thin lens with small aperture:
Answer
  • The equation which gives the relation between object-distance $u$ image distance $v$, and focal length $f$ of a lens is called the lens formula.
  • The lens formula for a thin lens with small aperture is $\frac{1}{v}-\frac{1}{u}=\frac{1}{f}$
  • Thin lens:
  • The lens for which the separation between the two surfaces, i.e., its thickness is much smaller (ignorable) than $u, v$ and $R$ is called a thin lens.
  • Small aperture :
  • The aperture which is much smaller than the radius of curvature of a lens is called a small aperature.
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Question 92 Marks
Find out from Table 2, the medium having highest optical density. Also, find the medium with lowest optical density.
Material medium Refractive index
Canada balsam $1.53$
Rock salt $1.54$
Carbon disulphide $1.63$
Dense flint glass $1.65$
Ruby $1.71$
Sapphire $1.77$
Diamond $2.42$
Answer
  • The higher the refractive index, the higher is the optical density.
  • Diamond has the highest optical density as it has the highest refractive index, $2.42$ and air has the lowest optical density as it has the lowest refractive index, $1.0003$.
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Question 102 Marks
Give the scientific reason : It is difficult to pierce a fish swimming in a river.
Answer
  • The rays of light from a swimming fish emerge from river - water and enter into air.
  • Thus, they travel from a denser medium to a rarer medium. Therefore they bend away from the normal at the interface.
  • Hence, the correct / true position of the fish cannot be determined by the observer from air That is why it is difficult to pierce a fish swimming in a river.
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Question 112 Marks
Give the scientific reason : The rear-view mirror (back-view mirror) of the vehicles is a convex mirror.
Answer
  • The field view of a convex mirror is very large, i.e., it gives over-all view of vast area of the backside of a vehicle and it forms a virtual, erect and diminished image of a backside object.
  • Hence, the vehicle can be driven safely by viewing backside fully.
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Question 122 Marks
Give the scientific reason : In a headlight, torch and search-light, a concave mirror (of small aperture) is used.
Answer
  • In a headlight, torch and search-light, the light source is placed at the principal focus of a concave mirror.
  • As a result, an intense parallel beam of light comes out from a headlight, torch, search-light.
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Question 132 Marks
A doctor has prescribed a corrective lens of power $+ 1.5 D$. Find the focal length of the lens. Is the prescribed lens diverging or converging?
Answer
  • Solution:
  • Here, Power $P=+1.5 D=+1.5 \ m^{-1}$
  • Focal length $f=$ ?
  • From, $f=\frac{1}{p^{\prime}}$
  • $f=\frac{1}{1.5 D}$
  • $=0.67 \ m$
  • $=67 \ cm$
  • As the power of the lens is positive (given), it is a converging lens, i.e., a convex lens.
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Question 142 Marks
Find the focal length of a lens of power $-2.0 D.$ What type of lens is this ?
Answer
  • Solution:
  • Here, Focal length of the lens $f=$ ?
  • Power $P=-2.0 D=-2.0 \ m^{-1}$
  • Now,
  • $As , P =\frac{1}{f}$
  • $f=\frac{1}{p}$
  • $=\frac{1}{-2 D}=-0.5 \ m$
  • $f=-50 \ cm$
  • As the power of the lens is negative (given), the lens must be concave.
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Question 152 Marks
The magnification produced by a plane mirror is $+1$. What does this mean?
Answer
  • Solution:
  • Here, $m=+1$
  • As,$m=\frac{h \prime}{h}$
  • $\frac{h \prime}{h}=+1$
  • $\therefore h^{\prime}= h$
  • So, the size of the image is equal to the size of object.
  • Further, the positive (plus) sign of $m$ indicates that the image is erect and hence virtual.
  • Again, $m=-\frac{v}{u}$ and $m=+1$
  • $\therefore-\frac{v}{u}=1$
  • $\therefore v=-u$
  • This shows that the image is formed behind the mirror and the distance of the image from the mirror equals that of the object from the mirror.
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Question 162 Marks
The refractive index of water is $1.33.$ What does it mean?
Answer
  • The refractive index of water is $n_w= 1.33.$
  • This means that the ratio of the speed of light in vacuum to the speed of light in water is equal to $1.33$.
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Question 172 Marks
Find the focal length of a convex mirror whose radius of curvature is $32 \ cm.$
Answer
  • Solution: Here, the radius of curvature $R = 32 \ cm$
  • We know that, the focal length $f=\frac{R}{2}$
  • $\therefore f=\frac{32}{2}=16 \ cm$
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Question 182 Marks
In case of a plane mirror, how will you locate the position of the image, with the mirror formula $\frac{1}{u}+\frac{1}{v}=\frac{1}{f}?$ 
Answer
  • In case of a plane mirror, the radius of curvature $R=$ infinity ( $\infty$ ). Also the focal length $f =$ infinity $(\infty)$
  • $\therefore$ From mirror formula, $\frac{1}{(-u)}+\frac{1}{v}=\frac{1}{\infty}$ (as per the sign convention)
  • $\therefore-\frac{1}{u}+\frac{1}{v}=0$
  • $\therefore u=v$
  • So, it can be said that the image is at the same distance from the mirror as the object distance from the mirror, but the image is formed behind the mirror.
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Question 192 Marks
Name a mirror that can give (form) an erect and enlarged image of an object.
Answer
  • Concave mirror
  • A concave mirror produces an erect and enlarged image of an object, when an object is placed between the pole and principal focus of the concave mirror.
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Question 202 Marks
How many rays at least are required to obtain the image formed by a spherical mirror? Why?
Answer
  • The image of an object, formed by spherical mirror, can be located by constructing a ray diagram.
  • For this, we may arbitrarily consider a large number of rays emanating from a point on an object but for the sake of clarity of ray diagram, it is more convenient to consider only two rays, as the intersection of at least two reflected rays gives the position of the image of the point on that object.
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Question 212 Marks
What is a plane mirror? Write the nature of an image formed by a plane mirror.
Answer
  • If the reflecting surface of a mirror is flat (plane), then the mirror is called a plane mirror.
  • The nature of an image formed by a plane mirror is as follows:
  • $(1)$ The image formed by a plane mirror is always virtual and erect.
  • $(2)$ The size of the image is equal to that of the object.
  • $(3)$ The image formed is as far behind the mirror, as the object is in front of it.
  • $(4)$ The image formed is laterally inverted, i.e., the left side of the object seems to be the right side of the image and vice versa.
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Question 222 Marks
What is a mirror?
Answer
  • A polished/ shining surface, which reflects almost all the light incident on it is called a mirror.
  • Mirrors are of two types: $(1)$ Plane mirror and $(2)$ Spherical mirror.
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Question 232 Marks
Give the scientific reason : For shaving as well as for make-up a concave mirror is used.
Answer
  • If a concave mirror is held such that the face is between the pole and principal focus of the concave mirror, a virtual, erect and magnified image of the face is obtained behind the mirror.
  • This is of great help in shaving as well as make-up.
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Question 242 Marks
Give the scientific reason : A big concave mirror is used in a solar furnace and solar cooker.
Answer
  • Parallel rays of light coming from, the Sun fall on the concave mirror fitted in a solar furnace and solar cooker and after reflection, these rays meet at the principal focus $F$ of the concave mirror.
  • The greater the aperture of the mirror, the greater is its power to collect light.
  • As a result, abundant amount of heat energy is produced.
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Question 252 Marks
What is light? Mention its nature.
Answer
  • Light is an electromagnetic radiation, which produces the sensation of sight in our eyes.
  • Normally, light has a wave nature.
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Question 262 Marks
Explain the terms for a convex lens : Focal length
Answer
  • The distance of the principal focus from the optical centre of a lens is called the focal length $f$ of the lens.
  • [Distance between $O$ and $F_1$ is called focal length $f_1$ and distance between $O$ and $F_2$ is called focal length $f_2$)
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Question 272 Marks
Explain the terms for a convex lens : Principal focus
Answer
  • When the rays parallel to the principal axis of a convex lens are refracted through the lens, they converge at a point on the principal axis. This point is called the principal focus $F$ of the convex lens.
  • When the rays parallel to the principal axis of a concave lens are refracted through the lens, they appear to diverge from a point on the principal axis.
  • This point is called the principal focus F of the concave lens.
  • A lens has two principal foci $F_1$ and $F_2$ on either side of the lens.
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Question 282 Marks
Explain the terms for a convex lens : Radius of curvature
Answer
  • The radius of a transparent (glass) sphere of which the curved surface of a lens forms a part is called the radius of curvature of the respective spherical surface of the lens.
  • Lens has two radii of curvatures $R_1$ and $R_2, R_1$ for surface $1$ and $R_2$ for surface $2$ of the lens.
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Question 292 Marks
Explain the terms for a convex lens : Optical centre
Answer
  • The central point of the lens, on the principal axis of the lens, is called the optical centre of the lens.
  • A ray of light through the optical centre passes without deviation.
  • Normally, it is denoted by $'O'$.
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Question 302 Marks
What do you mean by an optically denser medium and an optically rarer medium?
Answer
  • In comparing two media, the one with the higher refractive index is said to be optically denser than the other.
  • The other medium of lower refractive index is said to be optically rarer than the first one.
  • The speed of light is higher in an optically rarer medium than in an optically denser medium.
  • A ray of light travelling obliquely from an optically rarer medium to an optically denser medium slows down and bends towards the normal at the point of incidence.
  • While, when it travels from an optically denser medium to an optically rarer medium, it speeds up and bends away from the normal at the point of incidence.
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Question 312 Marks
What is optical density of a medium? Give brief information about it.
Answer
  • The ability of a medium to refract light is expressed in terms of its optical density.
  • Optical density has a definite connotation.
  • It is not the same as mass density.
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Question 322 Marks
What do you mean by refractive index of a medium?
Answer
  • A ray of light that travels obliquely from one transparent medium into another will change its direction in the second medium.
  • The extent of the change in direction that takes place in a given pair of media is expressed in term of the refractive index, the constant appearing in the equation $\frac{sin \ i}{sin\ r}=$ constant.
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Question 332 Marks
State the mirror formula and write it mathematically.
Answer
  • The relationship between the object distance $(u)$, the image distance $(v)$ and the focal length $(f)$ of a mirror is known as the mirror formula.
  • It is given by
  • $\frac{1}{v}+\frac{1}{u}=\frac{1}{f}.........(10,4)$
  • where, $u =$ the distance of the object from the pole of the spherical mirror
  • $v =$ the distance of the image from the pole of the spherical mirror
  • $f =$ the distance of the principal focus from the pole of the spherical mirror.
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Question 342 Marks
Why do we prefer a convex mirror as a rear-view mirror in vehicles?
Answer
  • This is because a convex mirror (always) forms an erect, virtual and diminished image of an object, wherever the object may be located.
  • Also, a convex mirror has a wider field of view, relative to a plane mirror, as it is curved outwards.
  • Thus, a convex mirror fitted on the side of a vehicle enables the driver to view much larger area than that would be possible with a plane mirror, enabling the driver to see traffic behind him/ her to facilitate safe driving.
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Question 352 Marks
Define the principal focus of a concave mirror.
Answer
  • The point on the principal axis of a concave mirror, at which rays of light incident on the mirror in a direction parallel to the principal axis (actually) meet/ intersect after reflection from the mirror is called the principal focus $(F)$ of the concave mirror.
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Question 362 Marks
What is reflection of light? Give the types of reflection.
Answer
  • The phenomenon of light rays bouncing back in the same medium on striking a (smooth) surface is called reflection of light.
  • Reflection is of two types: $(1)$ Regular reflection and $(2)$ Irregular (or diffused) reflection.
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Question 372 Marks
A pencil, when dipped obliquely in water in a transparent glass tumbler, appears to be bent at the interface of air and water. Will the pencil appear to be bent to the same extent, if instead of water we use some other liquid like kerosene or turpentine? Support your answer with reason.
Answer
  • Yes.
  • The angle of refraction depends on the refractive index of the medium.
  • So, bending will vary in different liquids.
  • It will be less for a liquid with low refractive index and more for a liquid with high refractive index.
  • The refractive index of kerosene as well as that of turpentine oil is more than that of water.
  • Hence, the bending will be more for both the oils than in case of water.
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Question 382 Marks
Raju focussed the image of a candle flame on a white screen using a convex lens. He noted the position of the candle as $26.0 \ cm$, the position of the convex lens as $50.0 \ cm$ and the position of the screen as $74.0 \ cm$. What is the focal length of the convex lens?
Answer
  • Here, $u =$ the distance of the candle from the convex lens $=-(50.0 - 26.0) = -24.0 \ cm$
  • $v =$ the distance of the screen from the convex lens $= (74.0 - 50.0) = 24.0 \ cm$
  • From the lens formula,
  • $\frac{1}{f}=\frac{-1}{u}+\frac{1}{v}$
  • $\therefore \frac{1}{f}=\frac{-1}{(-24)}+\frac{1}{24}=\frac{2}{24}$
  • $\therefore f=12 \ cm$
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Question 392 Marks
A concave lens produces an image at $20 \ cm$ from the lens of an object placed at $30 \ cm$ from the lens. Find the focal length of the lens.
Answer
  • Using the lens formula,
  • $\frac{1}{f}=\frac{-1}{u}+\frac{1}{v}$
  • $\frac{1}{f}=\frac{-1}{(-30)}+\frac{1}{-20}$
  • $\therefore \frac{1}{f}=\frac{1}{30}-\frac{1}{20}$
  • $=\frac{20-30}{(20)(30)}$
  • $=\frac{-10}{600}$
  • $=-\frac{1}{60}$
  • $\therefore f=-60 \ cm$
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Question 402 Marks
A $2\ cm$ high object is placed at a distance of $2f$ from a convex lens. What is the height of the image formed?
Answer
  • $m=\frac{v}{u}=\frac{h \prime}{h}$
  • $\therefore h ^{\prime}= h \left(\frac{v}{u}\right)$
  • Here, $u=-2 f$ and also $v=-2 f$ $\therefore$
  • he height of the image formed,
  • $h ^{\prime}=2 \ cm\left(\frac{-2 f}{-2 f}\right)(\because h=2 \ cm)$
  • $=2 \ cm$
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Question 412 Marks
An object is kept at $40 \ cm$ from a concave lens of focal length $60 \ cm$. Find the image distance.
Answer
  • Here, $u=-40 cm ; f=-60 \ cm$
  • Using the lens formula,
  • $\frac{1}{f}=\frac{-1}{u}+\frac{1}{v}$
  • We get
  • $\frac{1}{-60}=\frac{-1}{-40}+\frac{1}{v}$
  • $\therefore \frac{1}{v}=\frac{-1}{-40}-\frac{1}{60}$
  • $\therefore \frac{1}{v}=-\left(\frac{1}{40}+\frac{1}{60}\right)$
  • $\therefore v=-\left(\frac{60 \times 40}{40+60}\right)=-\frac{2400}{100}=-24 \ cm$
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Question 422 Marks
The magnification of an image formed by a convex lens is $-1$. Find the object distance in terms of its focal length.
Answer
  • Here, $m=-1$ and $u=-U$
  • So, from $m=\frac{v}{u}$
  • $-1=\frac{v}{(-u)}$
  • $\therefore v=+u$
  • Now, $\frac{1}{f}=\frac{-1}{u}+\frac{1}{v}$
  • $\therefore \frac{1}{f}=\frac{-1}{(-u)}+\frac{1}{(+u)}$
  • $\therefore \frac{1}{f}=\frac{2}{u}$
  • $\therefore u=2 f$
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Question 432 Marks
A concave mirror produces a real image of an object, placed at $10 \ cm$ from the mirror. If the image is enlarged by a factor of four relative to object, find the focal length of the mirror.
Answer
  • Here, $u =-10 \ cm$
  • As image formed is real and four times larger than object $m=-4$
  • Now, $m =\frac{v}{u}$
  • $\therefore-4=-\frac{v}{10} \therefore v=-40 \ cm$
  • Using the mirror formula,
  • $\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$
  • We get
  • $\therefore \frac{1}{f}=\frac{1}{(-10)}+\frac{1}{(-40)}$
  • $\therefore f=\frac{-40 x-10}{-40-10}=\frac{400}{-50}$
  • $\therefore f=-8 \ cm$
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[2 Mark Questions] - Science STD 10 Questions - Vidyadip