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Physics 1 Marks Question

PART - 2 CH - 13 Oscillations · Gujarat Board (GSEB) STD 11 Science (GSEB - English Medium). 35 questions.

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35 questions · timed · auto-graded

Question 11 Mark
Why is the necessary for a pendulum performing simple harmonic motion that its amplitude be less than its length?
Answer
Since $T=2 \pi \sqrt{\frac{l}{g}}$ in the formula of that $(\sin \theta=$ $\theta$ ) hence it is true only when $\theta$ is very small i.e. the dimension is less in comparison to the length
$ \because \quad \theta=\frac{\text { dimension }}{\text { length }} $
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Question 21 Mark
A man wearing a watch is falling down from a tower, will the watch show the correct time?
Answer
Yes, because the wrist watch depends on the functioning of the spring and g has no effect on it.
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Question 31 Mark
From where is the restoring force obtained for simple harmonic oscillation in a spring?
Answer
Restoring force is obtained
Simple Pendulum-Gravitational acceleration
Spring-Elasticity.
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Question 41 Mark
What will be the frequency of a pendulum hanging in the cabin, when falling freely?
Answer
The value of acceleration on freely objects is zero. Hence the frequency will also be zero.
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Question 51 Mark
The oscillator of a pendulum is negatively charged and a positively charged conductor plate is placed below it. The pendulum is made to oscillate. What will be the effect on the time period of the pendulum?
Answer
Attraction due to electric field between oscillator and plate. It will take force. Therefore, the effective value of g will increase, due to which the period will decrease.
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Question 61 Mark
At what position is the restoring force maximum on a particle performing simple harmonic motion?
Answer
At extreme position
$ F=-k x=-k A $
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Question 71 Mark
Why does a pendulum clock not work in an artificial earth satellite?
Answer
Oscillations do not occur due to weightlessness.
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Question 81 Mark
Write the acceleration, displacement and frequency of particle performing simple harmonic motion.
Answer
Acceleration $a=\omega^2 y$
$\text {or}\quad\quad\quad\quad a=(2 \pi n)^2 y=4 \pi^2 n^2 y $
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Question 91 Mark
A complete oscillation by a particle performing simple harmonic motion how much work is completed in?
Answer
Zero
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Question 101 Mark
What will the effect on time period if a hollow sphere of the same size is used instead of a solid iron sphere in a simple pendulum.
Answer
Will remains unchanged. Since the period does not depend on the mass of sphere.
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Question 121 Mark
The total energy of particle remains in simple harmonic motion.
Answer
Total energy $E =\frac{1}{2} m \omega^2 A^2$ remains constant.
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Question 131 Mark
Write the value of restoring force in a simple pendulum, when the angle of displacement is small.
Answer
$\begin{array}{l}\text { Restoring force } F =m g \sin \theta \\ \quad \theta \text { is less. } \quad \because \sin \theta=\theta \\ \therefore \text { Restoring force }= F =m g \theta\end{array}$
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Question 141 Mark
If the mass M is hung on a spring and it gets extended a distance x. What will be the magnitude of the force constant of that spring?
Answer
The magnitude of the force constant of the spring will be $\frac{m g}{x}$
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Question 151 Mark
Frequency of oscillations of a mass $M$ hanging from a spring $n_1$. If the length of the spring is cut to half, the same mass again oscillates with frequency $n_2$. Find the value of $\frac{n_2}{n_1}.$
Answer
$\frac{n_2}{n_1}=\sqrt{2}$
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Question 161 Mark
Ifa 1kg weight is hung from a light spring, it makes 4 oscillations in 1 second. If a 4 kg weight is hung from the same spring, how many oscillations will it make per second?
Answer
It will make two oscillations per second.
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Question 171 Mark
Under the condition is the minimum restoring force on a particle moving in simple harmonic motion?
Answer
In a state of equilibrium.
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Question 181 Mark
The total energy of a simple pendulum is E. What will be the kinetic energy and potential energy of the pendulum at the instant when the displacement of the pendulum is half of the amplitude?
Answer
Kinetic energy $=\frac{3 E }{4}$, Potential energy $=\frac{E}{4}$
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Question 191 Mark
If the potential energy at any position of a particle performing simple harmonic motion is half of the total energy, then what will be the displacement at that position?
Answer
$0-707~ \text {amplitude}$ 
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Question 201 Mark
If the acceleration of a particle simple $a=\left(-\frac{p}{q}\right) x$ harmonic motion is given, then what will be the time period of this particle?
Answer
Period $T =2 \pi \sqrt{\frac{q}{p}} l$.
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Question 211 Mark
What is the time difference between displacement and acceleration in simple harmonic motion ?
Answer
$\pi$ or $180^{\circ}$
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Question 221 Mark
If the oscillation amplitude of a simple pendulum is reduced to half of its present value, then what will be the value of its time period?
Answer
Will remain unchanged. Since the period does not depend on the amplitude.
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Question 231 Mark
Write the relationship between acceleratoin, displacement and frequency of a particle performing simple harmonic motion?
Answer
$a=-4 \pi^2 n^2 y =-\omega^2 y$
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Question 241 Mark
What will be the effect on the time period if a gold sphere of the same size is used instead of an iron sphere in a simple pendulum?
Answer
Will remains unchanged. Since there is no change in the effective lengrth, for this reason the period will remain unchanged.
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Question 251 Mark
A girl is swinging if the girl starts steep swinging, what will be the effect on the period?
Answer
The period will decrease. Since the center of mass will rise while standing, the effective length will reduce due to which the time period will decrease.
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Question 261 Mark
When the simple pendulum experiment is performed on Mount Abu the acceleration due to gravity reduce by 1%, what should be the change in the pendulum length to get the correct time from the pendulum clock?
Answer
These will be 91% decrease in the pendulum length.
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Question 271 Mark
What is the spring constant when the length of spring is $\frac{1}{n}$ ?
Answer
It will increase n times.
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Question 281 Mark
What will be the effect on the period of oscillation if a soft spring of the same length is used in place of a hard spring?
Answer
Will increase. Since the time period
$T =2 \pi \sqrt{\frac{m}{k}}$
The value of k for a soft spring is less than that for a hard spring.
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Question 291 Mark
If 0-1 kg the dimension of the body is 3 cm and if the oscillation period is 2 seconds, then what will be the value of total mechanical energy?
Answer
Total energy $=\frac{1}{2} m \omega^2 A^2$
$ \begin{aligned} & =\frac{1}{2} m(2 \pi n)^2 A^2 \\ & =\frac{1}{2} m\left(\frac{2 \pi}{T}\right)^2 A^2 \because n=\frac{1}{T} \\ \text { Keeping value } & =\frac{1}{2} \times 0.1\left(\frac{2 \pi}{2}\right)^2 \times(0.03)^2 \\ & =\frac{1}{2} \times 0.1 \times \pi^2 \times(0.03)^2 \text { Joule } \end{aligned} $
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Question 301 Mark
What is the relationship between the total energy and oscillation frequency of a simple pendulum?
Answer
$\begin{aligned} \text { Total energy } & =\frac{1}{2} m \omega^2 A^2 \\ \text { But } \omega & =2 \pi n \\ \text { Total energy } & =\frac{1}{2} m(2 \pi n)^2 A^2=2 \pi^2 m n^2 A^2\end{aligned}$
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Question 321 Mark
In simple harmonic motion by what phase angle is value of the displacement ahead of its acceleration value?
Answer
That is, simple harmonic motion the value of displacement is ahead of its acceleration by phase angle.
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Question 331 Mark
In a harmonic motion the initial phase is $\phi=\frac{3 \pi}{16}$. Express it in terms of period T .
Answer
The initial phase angle is $\phi=\frac{3}{32} T \because T =2 \pi$.
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Question 341 Mark
What is the initial phase angle of a body starting simple hormonic motion from the terminal end?
Answer
$\frac{\pi}{2}$
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Question 351 Mark
What is the relationship between acceleration and displacement for simple harmonic motion?
Answer
Acceleration $a \propto$ displacement.
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