Question 11 Mark
Find $\frac{d y}{d x}$ if $y=6 x^3+\frac{7}{2} x^2+\frac{6}{5} x-8$
Answer
View full question & answer→$y=6 x^3+\frac{7}{2} x^2+\frac{6}{5} x-8$
$\therefore \frac{d y}{d x}=18 x^2+7 x+\frac{6}{5}$
$\therefore \frac{d y}{d x}=18 x^2+7 x+\frac{6}{5}$