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Question 14 Marks
Explain logistic growth of population with the help of graph.
Answer
→ No population of any species in nature has at its disposal unlimited resources to permit exponential growth.
→ This leads to competition between individuals for limited resources. Eventually, the 'fittest' individual will survive and reproduce.
→ The government of many countries have also realised this fact and introduced various restraints with a view to limit human population growth.
→ In nature, a given habitat has enough resources to support a maximum possible number, beyond which no further growth is possible. Let us call this limit as nature's carrying capacity (K) for that species in that habitat.
→ A population growing in a habitat with limited resources show initially a lag phase, followed by phases of acceleration and deceleration and finally an asymptote, when the population density reaches the carrying capacity.
→ A plot of N in relation to time (t) results in a sigmoid curve.
→ This type of population growth is called Verhulst-Pearl Logistic Growth (Figure 11.3) and is described by the following equation:

Image

Where N = Population density at time t
r = Intrinsic rate of natural increase
K = Carrying capacity
→ Since resources for growth for most animal populations are finite and become limiting sooner or later, the logistic growth model is considered a more realistic one.
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Question 24 Marks
Explain the following :
(i) Competent Host
(ii) Isolation of the genetic material (DNA)
Answer
(i) Competent Host
→ Since DNA is a hydrophilic molecule, it cannot pass through cell membranes.
→ In order to force bacteria to take up the plasmid, the bacterial cells must first be made 'competent to take up DNA.
(a) Heat Shock :
→ This is done by treating them with a specific concentration of a divalent cation, such as calcium, which increases the efficiency with which DNA enters the bacterium through pores in its cell wall.
→ Recombinant DNA can then be forced into such cells by incubating the cells with recombinant DNA on ice, followed by placing them briefly at $42^{\circ}$ C (heat shock), and then putting them back on ice. This enables the bacteria to take up the recombinant DNA.
→ This is not the only way to introduce alien DNA into host cells.
→ Foreign gene can also be transfered to host by using following technique
(b) Micro injection :
→ In a method known as micro-injection, recombinant DNA is directly injected into the nucleus of an animal cell
(c) Biolistic or Gene Gun :
→ In another method, suitable for plants, cells are bombarded with high velocity micro-particles of gold or tungsten coated with DNA in a method known as biolistics or gene gun.
→ And the last method uses 'disarmed pathogen' vectors, which when allowed to infect the cell, transfer the recombinant DNA into the host.
→ Now that we have learnt about the tools for constructing recombinant DNA, let us discuss the processes facilitating recombinant DNA technology.
(ii) Isolation of the genetic material (DNA)
→ Recall that nucleic acid is the genetic material of all organisms without exception.
→ In majority of organisms this is deoxyribonucleic acid or DNA. In order to cut the DNA with restriction enzymes, it needs to be in pure form, free from other macro-molecules.
→ Since the DNA is enclosed within the membranes, we have to break the cell open to release DNA along with other macromolecules such as RNA, proteins, polysaccharides and also lipids.
→ This can be achieved by treating the bacterial cells/plant or animal tissue with enzymes such as lysozyme (bacteria), cellulase (plant cells), chitinase (fungus).
→ You know that genes are located on long molecules of DNA. interwined with proteins such as histones.
→ The RNA can be removed by treatment with ribonuclease whereas proteins can be removed by treatment with protease.
→ Other molecules can be removed by appropriate treatments and purified DNA ultimately precipitates out after the addition of chilled ethanol.
→ This can be seen as collection of fine threads in the suspension. (Figure 9.5)
Image
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Question 34 Marks
"Cancer detection, diagnosis and treatment" Discuss.
Answer
→ Early detection of cancers is essential as it allows the disease to be treated successfully in many cases.
→ Cancer detection is based on biopsy and histopathological studies of the tissue and blood and bone marrow tests for increased cell counts in the case of leukemias.
(a) Biopsy
→ In biopsy. a piece of the suspected tissue cut into thin sections is stained and examined under microscope (histopathological studies) by a pathologist.
(b) Radiation Diagnosis
→ Techniques like radiography (use of X-rays), CT (computed tomography) and MRI (magnetic resonance imaging) are very useful to detect cancers of the internal organs.
→ Computed tomography uses X-rays to generate a three-dimensional image of the internals of an object.
→ MRI uses strong magnetic fields and non-ionising radiations to accurately detect pathological and physiological changes in the living tissue.
(c) Pathological Diagnosis
→ Antibodies against cancer-specific antigens are also used for detection of certain cancers.
(d) Molecular Diagnosis
→ Techniques of molecular biology can be applied to detect genes in individuals with inherited susceptibility to certain cancers.
→ Identification of such genes, which predispose an individual to certain cancers, may be very helpful in prevention of cancers.
→ Such individuals may be advised to avoid exposure to particular carcinogens to which they are susceptible (e.g., tobacco smoke in case of lung cancer).
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Question 44 Marks
Explain metabolism of Lactose according to Jacob and Monod model. (Diagram is not required)
Answer
→ The elucidation of the lac operon was also a result of a close association between a geneticist, Francois Jacob and a biochemist, Jacque Monod.
→ They were the first to elucidate a transcriptionally regulated system.
→ In lac operon (here lac refers to lactose), a polycistronic structural gene is regulated by a common promoter and regulatory genes.
→ Such arrangement is very common in bacteria and is referred to as operon.
→ The lac operon consists of one regulatory gene (the i gene here the term i does not refer to inducer, rather it is derived from the word inhibitor) and three structural genes (z, y, and a).
→ The i gene codes for the repressor of the lac operon.
→ The z gene codes for beta-galactosidase ($\beta$-gal), which is primarily responsible for the hydrolysis of the disaccharide, lactose into its monomeric units, galactose and glucose.
→ The y gene codes for permease, which increases permeability of the cell to $\beta$-galactosides.
→ The a gene encodes a transacetylase.
→ Hence, all the three gene products in lac operon are required for metabolism of lactose. In most other operons as well, the genes present in the operon are needed together to function in the same or related metabolic pathway.
→ Inducer :
→ Lactose is the substrate for the enzyme beta-galactosidase and it regulates switching on and off of the operon. Hence, it is termed as inducer.
→ In the absence of a perferred carbon source such as glucose, if lactose is provided in the growth medium of the bacteria, the lactose is transported into the cells through the action of permease (Remember, a very low level of expression of lac operon has to be present in the cell all the time, otherwise lactose cannot enter the cells).
→ The lactose then induces the operon in the following manner.
→ The repressor of the operon is synthesised (all-the-time-constitutively) from the i gene. The repressor protein binds to the operator region of the operon and prevents RNA polymerase from transcribing the operon.
→ In the presence of an inducer, such as lactose or allolactose, the repressor is inactivated by interaction with the inducer.
→ This allows RNA polymerase access to the promoter and transcription proceeds. Essentially, regulation of lac operon can also be visualised as regulation of enzyme synthesis by its substrate.
→ Remember, glucose or galactose cannot act as inducers for lac operon.
→ Lac operon would remain expressed untill all the amount of lactose is converted to glucose & Galactose.
→ Regulation of lac operon by repressor is referred to as negative regulation. Lac operon is under control of positive regulation as well, but it is beyond the scope of discussion at this level.
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Question 54 Marks
Give detailed account about colour blindness and sickle cell anemia. (Diagram is not require)
Answer
→ Sickle-cell anaemia : This is an autosome linked recessive trait that can be transmitted from parents to the offspring when both the partners are carrier for the gene (or heterozygous).
→ The disease is controlled by a single pair of allele, HbA and HbS. Out of the three possible genotypes, only homozygous individuals for HbS (HbSHbS) show the diseased phenotype.
→ Heterozygous (HbAHbS) individuals appear apparently unaffected but they are carrier of the disease as there is 50 per cent probability of transmission of the mutant gene to the progeny, thus exhibiting sickle-cell trait
→ The defect is caused by the substitution of Glutamic acid (Glu) by Valine (Val) at the sixth position of the beta globin chain of the haemoglobin molecule
→ The substitution of amino acid in the globin protein results due to the single base substitution at the sixth codon of the beta globin gene from GAG to GUG.
→ The mutant haemoglobin molecule undergoes polymerisation under low oxygen tension causing the change in the shape of the RBC from biconcave disc to elongated sickle-like structure.
Image
→ Micrograph of the red blood cells and the amino acid composition of the relevant portion of $\beta$-chain of haemoglobin: (a) From a normal individual; (b) From an individual with sickle-cell anaemia
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Question 64 Marks
Draw labelled diagram of the female reproductive system and explain about structure of uterus.
Answer

Image
→ The oviducts (fallopian tubes), uterus and vagina constitute the female accessory ducts.
→ Structure of Oviducts :
→ Each fallopian tube is about 10-12 cm long.
→ It extends from the periphery of each ovary to the uterus.
→ The part closer to the ovary is the funnel-shaped infundibulum.
→ The edges of the infundibulum possess finger-like projections called fimbriae, which help in collection of the ovum after ovulation.
→ The infundibulum leads to a wider part of the oviduct called ampulla.
→ The last part of the oviduct, isthmus has a narrow lumen and it joins the uterus.
→ Structure of Uterus :
→ The uterus is single and it is also called womb.
→ The shape of the uterus is like an inverted pear.
→ It is supported by ligaments attached to the pelvic wall.
→ The wall of the uterus has three layers of tissue.
(i) The external thin membranous perimetrium.
(ii) middle thick layer of smooth muscle, myometrium.
(iii) inner glandular layer called endometrium that line the uterine cavity.
→ The endometrium undergoes cyclical changes during menstrual cycle while the myometrium exhibits strong contraction
during delivery of the baby.
→ The uterus opens into vagina through a narrow cervix.
→ The cavity of the cervix is called cervical canal which along with vagina forms the birth canal.
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4 Marks Question - BIOLOGY STD 12 Science Questions - Vidyadip