403 questions across 7 question groups — pick any mix to generate a Chemistry paper with step-by-step answer keys.
2 Marks Questions
70 Q→023 Marks Question
60 Q→031 Marks Question
65 Q→04Case study (4 Marks)
9 Q→05M.C.Q (1 Marks)
169 Q→06Assertion (A) & Reason (B) MCQ
18 Q→075 Marks Questions
12 Q→One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
| Concentration/M | 0.001 | 0.010 | 0.020 | 0.050 | 0.100 |
| 102× k/S m-1 | 1.237 | 11.85 | 23.15 | 55.53 | 106.74 |
I2 + 2e- → 2I- ; Eº = 0.54 V
Cl2 + 2e- → 2Cl- ; Eº = 1.36 V
Mn3+ +e- → Mn2+ ; Eº = 1.50 V
Fe3+ + e- → Fe2+ ; Eº = 0.77 V
O2 + 4H+ + 4e- → 2H2O ; Eº = 1.23 V
The following questions are multiple choice questions. Choose the most appropriate answer:$\text{I}_2+\text{KCl}\rightleftharpoons2\text{KI}+\text{Cl}_2$
Fe3+ + Mn2+ → Fe2+ + Mn3+
For spontaneous cell reaction, C1 < C2
Reason: For concentration cell, $\text{E}_\text{cell}=\frac{\text{RT}}{\text{nF}}\log\frac{\text{C}_2}{\text{C}_1}$
For spontaneous reaction, $\text{E}_\text{cell}=+\text{ve}\Rightarrow\text{C}_2>\text{C}_1$
Reason: At the equilibrium, there is no change in concentration of Cu2+ and Zn2+ ions.
Reason: In a cell, current flows from cathode to anode.
Reason: $\text{E}_\text{cell}=\text{E}^\circ_\text{cell}+\frac{0.059}{2}\log\frac{[\text{Cu}^{2+}]}{[\text{Zn}^{2+}]}$
$\text{E}=\text{E}^\circ+\frac{0.059}{\text{n}}\log[\text{Mn}^{+}]$
Reason: STP conditions require the temperature to be 273K.
Reason: A reaction is spontaneous if the free energy change is negative.
Reason: It is by convention.
Reason: Strength of reducing agent increases with the increase in negative value of the standard reduction potential.
Reason: The standard electrode potential of a half cell has a fixed value.
Reason: The electrode potential values are generally determined with respect to SHE.
Reason: Eº should be positive for a spontaneous reaction.
Reason: A reaction is spontaneous if free energy change is negative.
Reason: The given cell is non-spontaneous.
Reason: Equilibrium of the cell reaction is attained.
Reason: Ecell = Ecathode - Eanode
| | Column I | | Column II |
| i. | Lechlanche cell | a. | Cell reaction 2H2 + O2 ⎯→ 2H2O |
| ii. | Ni–Cd cell | b. | Does not involve any ion in solution and is used in hearing aids. |
| iii. | Fuel cell | c. | Rechargeable. |
| iv. | Mercury cell | d. | Reaction at anode, Zn ⎯→ Zn2+ + 2e- |
| | | e. | Converts energy of combustion into electrical energy. |
| | Column I |
| Column II |
| i. | $\text{K}$ | a. | $\text{I}\times\text{t}$ |
| ii. | $\wedge_{\text{m}}$ | b. | $\frac{\wedge_{\text{m}}}{\wedge^\circ_\text{m}}$ |
| iii. | $\alpha$ | c. | $\frac{\text{k}}{\text{c}}$ |
| iv. | $\text{Q}$ | d. | $\frac{\text{G}^*}{\text{R}}$ |
| | Column I |
| Column II |
| i. | $\wedge_{\text{m}}$ | a. | Intensive property. |
| ii. | $\text{E}^{\ominus}_{\text{Cell}}$ | b. | Depends on number of ions/volume. |
| iii. | $\text{K}$ | c. | Extensive property. |
| iv. | $\Delta_{\text{r}}\text{G}_{\text{Cell}}$ | d. | Increases with dilution. |
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