$\sin\Big\{2\cos^{-1}\Big(\frac{-3}{5}\Big)\Big\}$ is equal to:
View full solution →- $\frac{6}{25}$
- $\frac{24}{25}$
- $\frac{4}{5}$
- $-\frac{24}{25}$
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$9\text{x}^2-12\text{xy}\cos\alpha+4\text{y}^2=36\sin^2\alpha.$
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