Question 11 Mark
A pure inductor of $25.0 mH$ is connected to a source of $220 V$. Find the inductive reactance and rms current in the circuit if the frequency of the source is $50 Hz$.
Answer
View full question & answer→The inductive reactance,
$
\begin{aligned}
X_L & =2 \pi v L=2 \times 3.14 \times 50 \times 25 \times 10^{-3} \Omega \\
& =7.85 \Omega
\end{aligned}
$
The rms current in the circuit is
$
I=\frac{V}{X_L}=\frac{220 V }{7.85 \Omega}=28 A
$
$
\begin{aligned}
X_L & =2 \pi v L=2 \times 3.14 \times 50 \times 25 \times 10^{-3} \Omega \\
& =7.85 \Omega
\end{aligned}
$
The rms current in the circuit is
$
I=\frac{V}{X_L}=\frac{220 V }{7.85 \Omega}=28 A
$





