The wavelength $\lambda$, frequency $v$, velocity $v$ and intensity I of a light ray transmitted in air respectively. If this ray enters water, then the values of these quantities become $\lambda^{\prime}, \nu^{\prime}, v^{\prime}$ and $I^{\prime}$ respectively. Which of the following relations is correct?
The wavelength of light used in an optical instrument is $\lambda_1=4000 Å$ and $\lambda_2=5000 Å$. The ratio of their corresponding resolution powers will be :
Two coherent sources whose frequency ratio is $100: 1$ used to generate interference fringes. The ratio of maximum and minimum intensity in fringes will be :
The angle of incidence of a ray of light on a transparent substance is $60^{\circ}$. The reflected ray is completely polarized. The refractive index of the material is :
In the Fraunhofer diffraction experiment of single aperture, the condition of path difference ( $\Delta$ ) for the secondary maximum of $n^{\text {th }}$ order is :
In Young's double slit experiment, the wavelength is $6000 Å$, the screen is at a distance of 40 cm from the slits and the distance between the fringes is $0.012 cm $, then the separation between the slits will be :
Distance between two slits $S_1$ and $S_2$ in Young's double slit experiment is 1 mm . What should be the width of each slit so that the $10^{\text {th }}$ maximum of the double slit is obtained at the central maximum of the slit?
Two light waves of intensities I and 4I, makes fringes by interference. The phase difference between the waves at point A of the screen is $\pi / 2$ and at point B is $\pi$. Then at point A and B the difference between the resulting intensities is :
The displacement at point P by two light waves emitted from this light source is $Y _1=5 \sin \omega t$ and $Y _2$ $=3 \cos \omega t$ respectively, then both the waves will be :
In Young's double slit experiment, at a fixed point where $\lambda$ is path difference $=\lambda / 6(\lambda=$ wavelength of the light used), the intensity is I. If $I _0$ is the maximum intensity then $I / I_0$ is equal to :
Two waves of same amplitude and same wavelength are superimposed in different phases. The amplitude of the resultant wave will be maximum when the phase difference between them is: