Write the first four products of two numbers with difference 4 starting from in the following order:
1, 2, 3, 4, 5, 6, ........
Identify the pattern in the products and write the next three products.
Answer$1 \times 5=5 $
$ 2 \times 6=12 $
$ 3 \times 7=21 $
$ 4 \times 8=32$
Pattern:
$1 \times 5=\left(\frac{1+5}{2}\right)^2-4 $
$2 \times 6=\left(\frac{2+6}{2}\right)^2-4 $
$3 \times7=\left(\frac{3+7}{2}\right)^2-4 $
$4 \times 8=\left(\frac{4+8}{2}\right)^2-4 $
$5 \times 9=\left(\frac{5+9}{2}\right)^2-4 $
$6 \times 10=\left(\frac{6+10}{2}\right)^2-4$