case /data -based (4 Marks)

Question 14 Marks

Vibhor has a keen interest to invest in the share market. His investment consultant advised him to study the fluctuations in the values of certain shares over a period of 5 days. Vibhor found that on July 1, the price of one share of ABC company was ₹3735.
Q.1. On July 2, the price of the share increased by ₹ 147. What was the price of each share of ABC company on July 2?
(a) ₹3582$\quad$(b) ₹3872$\quad$(c) ₹3882$\quad$(d) ₹3588
Q.2. On July 3, the share opened 27 below the previous day closing and again slipped by ₹9 by the end of the day. At what price did the share close on July 3?
(a) ₹3900 $\quad$(b) ₹3864$\quad$(c)₹ 3873 $\quad$(d) ₹3846
Q.3. On July 4, the share opened 128 above the previous day closing but again went down by ₹76 by the end of the day. What was the price of each share of ABC company at the end of the day on July 4?
(a) ₹3898$\quad$(b) ₹4050$\quad$(c) ₹3642$\quad$(d) ₹3787
Q.4. On July 5, the price of the share jumped ₹291 when the market opened. It rose further by ₹66 by the end of the day. What was the price of the share at the end of the day on July 5?
(a) ₹4123$\quad$(b) ₹3673$\quad$(c) ₹3541 $\quad$(d) ₹4255

Answer

1. (c) ₹3882: Price of the share on July 2 = ₹ (3735 + 147) = ₹3882.
2. (d) ₹3846: Price of the share at the end of July 2 = ₹ 3882.
Price at the end of July 3 = ₹ (3882 - 27 – 9) = ₹3846.
3. (a)₹3898: Price of the share at the end of July 3 = ₹ 3846.
Price at the end of July 4 = ₹ (3846 + 128 - 76) = ₹3898.
4. (d)₹4255: Price of the share at the end of July 4 = ₹3898.
Price at the end of July 5 = ₹ (3898 + 291 + 66) = ₹4255.

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Question 24 Marks

Sameer arranged a vacation to Thailand with his children during their holidays. They were all excited to go scuba diving on the Coral Islands. Sameer dived 43 feet to reach the brain coral upon the directions of his instructor. He then rose by 18 feet to reach an underwater cave.
Q.1. What is the depth of the underwater cave?
(a) 18 feet$\quad$(b) 61 feet$\quad$(c) 25 feet$\quad$(d) 43 feet
Q.2. Sameer again dived 56 feet to reach the base of the reef. What is the depth of the reef?
(a) 56 feet$\quad$(b) 74 feet $\quad$(c) 99 feet $\quad$(d) 81 feet
Q.3. From the base of the reef, Sameer ascended 29 feet and reached a ridge. How deep is the ridge with respect to sea level?
(a) 52 feet$\quad$(b) 110 feet$\quad$(c) 85 feet$\quad$(d) 95 feet
Q.4. A whale passed at a depth of 23 feet from the sea level. How far was the whale from the ridge?
(a) 23 feet$\quad$(b) 81 feet$\quad$(c) 29 feet$\quad$(d) 52 feet

Answer

1. (c) 25 feet : Depth of the underwater cave = (-43 +18) feet = (-25) feet.
Thus, the depth of the underwater cave is 25 feet (below sea level).
2. (d) 81 feet: Sameer's position (when he was at the underwater cave) = (-25) feet.
He dived further down by 56 feet to reach the base of the reef.
Location of the base of the reef = (-25-56) feet = (-81) feet.
Thus, the depth of the reef is 81 feet (below sea level).
3. (a) 52 feet: Sameer's position (when he was at the base of the reef) = (-81) feet.
He ascended 29 feet to reach the ridge.
Location of the ridge = (-81+29) feet = (-52) feet.
So, the location of the ridge is 52 feet (below sea level).
4. (c) 29 feet : Sameer's location (at the ridge) =(-52) feet.
Whale's location = (-23) feet.
Distance of the whale from the ridge = {-23 -(-52)} feet = (-23 +52) feet = 29 feet.

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MATHS case /data -based (4 Marks)

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