Question 11 Mark
$\frac{-5}{-8}$ lies on the right of $\frac{-5}{7}$ on the number line.
Answer
View full question & answer→self
15 questions · timed · auto-graded
Solution:
LCM of 5, 10 and 6 is 30
$\therefore\frac{-3\times6}{5\times6}=\frac{-18}{30}$
$\frac{-7\times3}{10\times3}=\frac{-21}{30}$
and $\frac{-5\times5}{-6\times5}=\frac{-25}{30}$
$\therefore\frac{-3}{5}$ is the largest among the given fractions.
Solution:
This is because $\frac{-15}{-11}=\frac{15}{11}$ which lies to the right of 0.