Sample QuestionsSimple Interest questions
One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
Mark $(\checkmark)$ against the correct answer in the following: A borrows $Rs. 8000$ at $12\%$ per annum simple interest and $B$ borrows $Rs. 9100$ at $10\%$ per annum simple interest. In how many years will their amounts be equal$?$
- A
$18$ years
- B
$20$ years
- ✓
$22$ years
- D
$24$ years
Answer: C.
View full solution →Mark $(\checkmark)$ against the correct answer in the following: A sum amounts to $Rs.3605$ in $219$ days at $5\%$ per annum. The sum is:
- A
$Rs. 3250$
- ✓
$Rs. 3500$
- C
$Rs. 3400$
- D
$Rs. 3550$
Answer: B.
View full solution →Mark $(\checkmark)$ against the correct answer in the following: In what time will $Rs. 6000$ amount to $Rs. 6360$ at $8\%$ interest per annum simple interest$?$
- ✓
$9\text{ months}$
- B
$\text{8 months}$
- C
$1\frac14\text{ years}$
- D
$1\frac12\text{ years}$
Answer: A.
View full solution →Mark $(\checkmark)$ against the correct answer in the following: The simple interest on $Rs. 6250$ at $4\%$ per annum for $6$ months is:
- ✓
$Rs. 125$
- B
$Rs. 150$
- C
$Rs. 175$
- D
$Rs. 135$
Answer: A.
View full solution →Mark $(\checkmark)$ against the correct answer in the following: The simple interest on a sum for $5$ years is $\frac25$ of the sum. The rate percent per annum is:
- A
$10\%$
- ✓
$8\%$
- C
$6\%$
- D
$12\frac12\%$
Answer: B.
View full solution →Assertion (A): A sum of money doubles itself in 10 years. The rate of interest is $10 \%$ p.a.
Reason ( $R$ ): At the same rate, the money will treble itself in 15 years.
View full solution →Assertion (A): Sudhir took a loan of ₹ 64,000 from a bank at $6 \%$ p.a. for 2 years. After 2 years he has to pay ₹ 71,680 to the bank.
Reason (R): Sudhir lent this amount of ₹ 64,000 to Namit at $10 \%$ p.a. for 2 years. After 2 years he will earn ₹ 5,720.
View full solution →Assertion (A): If $₹ x$ is the SI on a certain sum for $x$ years at $x \%$ p.a. then the sum is $₹\left(\frac{100}{x}\right)$.
Reason (R): $P=\frac{100 \times SI }{R \times T} ;$ where P= principal, R= rate % p.a., T= time and SI = simple interest.
View full solution →$\text{Rate}=\frac{100\times\text{S.I.}}{\text{P}\times\text{T}}$
View full solution →Simple interest on Rs. x for x years is Rs. x. Then, the rate of interest is x % per annum.
Simple interest on Rs. 1000 at 5% per annum for 73 days is Rs. 10.
A sum doubles itself at simple interest at 10% per annum in 10 years.
$\text{R}=\frac{100\times\text{S.I.}}{(.......)\times\text{T}}$
View full solution →$\text{P}=\frac{100\times(......)}{\text{R}\times\text{T}}$
View full solution →AT simple interest a sum becomes $\frac65$ of itself in $2\frac12\text{ years.}$ The rate of interest is (......)% per annum.
View full solution →AT (....)% per annum simple interest a sum doubles itself in 10 years.
Write $‘T’$ for true and $‘F’$ for false for the following: Simple interest on $Rs. 1000$ at $5\%$ per annum for $73$ days is $Rs. 10$.
View full solution →Fill in the blanks: $AT$ simple interest a sum becomes $\frac65$ of itself in $2\frac12\text{ years.}$ The rate of interest is (......)% per annum.
View full solution →Write $‘T’$ for true and $‘F’$ for false for the following:
A sum doubles itself at simple interest at $10\%$ per annum in $10$ years.
View full solution →Fill in the blanks: $\text{R}=\frac{100\times\text{S.I.}}{(.......)\times\text{T}}$
View full solution →Fill in the blanks: $AT (....)\%$ per annum simple interest a sum doubles itself in $10$ years.
View full solution →Find the simple interest on $Rs. 6300$ at $8\%$ per annum for $8$ months.
View full solution →Find the time when: A sum when reckoned at $7\frac12\%$ per annum amounts to $Rs. 3920$ in $3$ years. Find the sum.
View full solution →Find the time when: A sum of money lent at simple interest amounts to $Rs. 783$ in $2$ years and to $Rs. 837$ in $3$ years. Find the sum and the rate per cent per annum.
View full solution →Find the time when: A sum of money becomes $\frac85$ of itself in $5$ years at a certain rate of simple interest. Find the rate of interest.
View full solution →Find the time when: If $Rs. 640$ amounts to $Rs. 768$ in $2$ years $6$ months. What will $Rs. 850$ amount to in $3$ years at the same rate per cent per annum?
View full solution →Find the time when: A sum of money invested at $8\%$ per annum amounts to $Rs. 12122$ in $2$ years. What will it amount to in $2$ years $8$ months at $9\%$ per annum?
View full solution →Mr Tiwari has two choices of investing his money. If he invests in a bank, he gets 10% simple interest. If he invests in his friend's company SIB, he gets 15% simple interest.
Q.1. If Mr Tiwari invests ₹6,00,000 with the bank, the interest that he receives after 2 years will be
(a) ₹1,10,000$\quad$(b) ₹1,20,000$\quad$(c)₹ 60,000$\quad$(d) ₹₹80,000
Q.2. What sum invested in SIB company will amount to 6,65,000 in 6 years?
(a) ₹3,50,000$\quad$(b)₹4,00,000$\quad$(c)₹4,25,000$\quad$(d)₹4,50,000
Q.3. How long will it take the money invested in SIB company to become four times of itself?
(a) 12 years(b) 15 years(c) 20 years(d) 24 years
Q.4. Mr Tiwari wishes to invest ₹6,00,000 partly in the bank and partly in SIB company such that after 2 years, he receives the same interest from both. Find the sum that he should invest in the bank.
(a) ₹3,00,000$\quad$(b) ₹3,30,000$\quad$(c) ₹3,60,000$\quad$(d) ₹2,40,000
View full solution →Find the simple interest and the amount when:
Principal $= Rs. 2650,$ rate $= 8\%$ p.a. and time $=2\frac12\text{ years.}$
View full solution →Find the time when: Principal $= Rs. 8250, S.I. = Rs. 1100$ and time $= 2$ years.
View full solution →Find the time when:
In what time will $Rs. 5600$ amount to $Rs. 6720$ at $8\%$ per annum$?$
View full solution →Find the time when:
The simple interest on a certain sum for $3$ years at $10\%$ per annum is $Rs. 829.50.$ Find the sum.
View full solution →At what rate percent per annum simple interest will $Rs. 3625$ amount to $Rs. 4495$ in $2$ years$?$
View full solution →