Download App

Linear Equations in One Variable MATHS - Linear Equations in One Variable

Gujarat Board (GSEB) - STD 8 - MATHS (GSEB - English Medium). 61 questions in this chapter.

Question types

Linear Equations in One Variable question types

61 questions across 8 question groups — pick any mix to generate a MATHS paper with step-by-step answer keys.

61
Questions
8
Question groups
5
Question types
Sample Questions

Linear Equations in One Variable questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Q 11Assertion (A) & Reason (B) MCQ1 Mark
Assertion (A) A linear equation in one variable has exactly one solution.
Reason (R) The solution of a linear equation in the value of the variable. That satisfies the equation and places both sides in balance.
  • ✓
    Both A and R are true and R is the correct explanation of A.
  • B
    Both A and R are true but R is not the correct explanation of A .
  • C
    A is true but R is false.
  • D
    A is false but R is true.

Answer: A.

View full solution →
Q 12Assertion (A) & Reason (B) MCQ1 Mark
Assertion (A) The value of $3 x+5=2$ is same as $3 x+7=4$.
Reason (R) Adding the same value to both sides maintains the balance between the two sides of the equation.
  • ✓
    Both A and R are true and R is the correct explanation of A.
  • B
    Both A and R are true but R is not the correct explanation of A .
  • C
    A is true but R is false.
  • D
    A is false but R is true.

Answer: A.

View full solution →
Q 13Assertion (A) & Reason (B) MCQ1 Mark
Assertion (A) The standard form of a linear equation in one variable $x$ is $a x+b=0$
Reason (R) Linear equation in one variable is $a x=0$, where $x$ is variable and $a$ is arbitrary constant.
  • A
    Both A and R are true and R is the correct explanation of A.
  • ✓
    Both A and R are true but R is not the correct explanation of A .
  • C
    A is true but R is false.
  • D
    A is false but R is true.

Answer: B.

View full solution →
Q 245 Marks Questions5 Marks
Sasha solves a linear equation. Her work is shown below
$\begin{aligned} 2 x-3 & =\frac{x}{2}-5 \\ 2(2 x-3) & =x-5 \ldots \ldots \text { Step } 1 \\ 4 x-6 & =x-5 \ldots \ldots \text { Step } 2 \\ 4 x-x & =6-5 \ldots \ldots \text { Step } 3 \\ 3 x & =1 \ldots \ldots \text { Step } 4 \\ x & =\frac{1}{3}\end{aligned}$
Is Sasha's solution correct? If not, in which step did Sasha make an error?
View full solution →
Q 265 Marks Questions5 Marks
Find the value of $2 m+\frac{1}{2} n$, if $m$ and $n$ are the solutions of the equations $\frac{m+3}{7-2 m}=\frac{1}{2}$ and $\frac{1}{4}(n+4)=2 n-3$, respectively.
View full solution →
Q 275 Marks Questions5 Marks
Game : Who will be the Lakhpati?
Rohit and Saurabh are playing a game. The one who solves the following equations will be a winner. Find out if you were at their place would you have been be a winner. Till what money did you reach successfully?
Rules of the game
(a) You can only move to the next problem if the previous answer is correct.
(b) Winning amount slab
Question NumberAmount Won
1₹ 1000
2₹ 2000
3₹ 3000
4₹ 4000
5₹ 10000
6₹ 12000
7₹ 14000
8₹ 20000
9₹ 40000
10₹ 100000
(c) Problems:
(i) $\frac{x+1}{2 x+7}=\frac{3}{8}$
(ii) $\frac{1}{(x-1)}+\frac{2}{(x+1)}=2$
(iii) $\frac{6 x+1}{3}+1=\frac{x-3}{6}$
(iv) $3 m=7 m-\frac{8}{7}$
(v) $-x=\frac{-6}{5}(x-10)$
(vi) $5 x+\frac{7}{2}=\frac{3}{2} x-14$
(vii) $\frac{x}{3}+1=\frac{8}{15}$
(viii) $\frac{x}{2}+\frac{3 x}{4}-\frac{5 x}{6}=2$
(ix) $\frac{50}{x}+4=14$
(x) $x+\frac{2}{3} x+\frac{x}{7}=97-\frac{x}{2}$
View full solution →
Q 285 Marks Questions5 Marks
Ranika wanted her friend Radhika's mobile number. But Radhika played a trick. She gave her the number as
$9 X Y Z P 1 Q 2 R 3$
and told her to decode it with the help of following equations:
(a) $16 X-35=7 X-8$
(b) $\frac{6 Y-7}{3 Y+9}=\frac{1}{3}$
(c) $\frac{4 Z-5}{8+6 z}=\frac{3}{20}$
(d) $P+\frac{3}{10} P=\frac{13}{10}$
(e) $4(Q+4)=5(Q+2)$
(f) $3(R+10)+200=236$
View full solution →
Q 30MATCH THE FOLLOWING.4 Marks
Match the Column A with Column B.
Column AColumn B
(a) 7(i) $\frac{x}{5}=\frac{x-1}{6}$
(b) -5(ii) $5(0.2 x+5)=2(3.5 x-3)$
(c) $\frac{31}{6}$(iii) $8 x-7-3 x=6 x-2 x-3$
(d) 4(iv) $5(x-1)-2(x+8)=0$
View full solution →
Browse all question groups ↑

Generate a Linear Equations in One Variable paper free

Pick question groups from the list above, set marks and difficulty, and export a branded PDF with step-by-step answer keys. First 3 chapters free — no signup.

Download App
Generate Paper FreeAll MATHS chapters