Assertion (A) & Reason (B) MCQ

MCQ 11 Mark

Assertion (A) : Out of 100 cards bearing numbers 1 to 100, one card is drawn at random. Then, the probability of getting a two-digit number is $\frac{9}{10}$.
Reason (R) : There are 90 two-digit numbers in all.

✓
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
B
Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of Assertion (A).
C
Assertion (A) is true but Reason (R) is false.
D
Assertion (A) is false but Reason (R) is true.

Answer

Correct option: A.

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

(a): Total number of possible outcomes $=100$
Number of favourable outcomes $=$ number of two-digit numbers $=90$.
$\therefore \quad$ required probability $=\frac{90}{100}=\frac{9}{10}$.

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MCQ 21 Mark

Assertion (A) : The probability of an event cannot be negative.
Reason (R) : The probability of an impossible event is 0.

✓
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
B
Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of Assertion (A).
C
Assertion (A) is true but Reason (R) is false.
D
Assertion (A) is false but Reason (R) is true.

Answer

Correct option: A.

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

(a)

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MCQ 31 Mark

Assertion (A) : In rolling a die, the probability of getting an odd prime number is$\frac{1}{3}$.
Reason (R) : 1,3 and 5 are odd prime numbers.

A
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
B
Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of Assertion (A).
✓
Assertion (A) is true but Reason (R) is false.
D
Assertion (A) is false but Reason (R) is true.

Answer

Correct option: C.

Assertion (A) is true but Reason (R) is false.

(c): 3 and 5 are odd prime numbers.
$\therefore \quad \text { required probability }=\frac{2}{6}=\frac{1}{3} \text {. }$

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MCQ 41 Mark

Assertion (A) : The probability of occurrence of an event may be greater or smaller than 1.
Reason (R) : The probability of a sure event is 1.

A
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
B
Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of Assertion (A).
C
Assertion (A) is true but Reason (R) is false.
✓
Assertion (A) is false but Reason (R) is true.

Answer

Correct option: D.

Assertion (A) is false but Reason (R) is true.

(d): The probability of an event cannot be greater than 1 , as the probability of sure event is 1 .
Hence, A is false but R is true.

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MCQ 51 Mark

Assertion (A) : If two coins are tossed together then the probability of not getting a head is $\frac{1}{4}$.
Reason (R) : Out of the total 4 outcomes, only one outcome of getting two tails is favourable.

✓
Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
B
Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of Assertion (A).
C
Assertion (A) is true but Reason (R) is false.
D
Assertion (A) is false but Reason (R) is true.

Answer

Correct option: A.

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

(a): Possible outcomes are $H H, H T, T H, T T$.
$\therefore \quad P(\text { not getting a head })=P(\text { getting both tails })=\frac{1}{4} .$

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MATHS Assertion (A) & Reason (B) MCQ

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