Question types

Exponents Of Real Numbers [NEW] question types

217 questions across 7 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.

217
Questions
7
Question groups
5
Question types
Sample Questions

Exponents Of Real Numbers [NEW] questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Q 1M.C.Q1 Mark
Which of the following is not equal to $\left\{\left(\frac{5}{6}\right)^{1 / 5}\right\}^{-1 / 6} ?$
  • $\left(\frac{5}{6}\right)^{\frac{1}{5}-\frac{1}{6}}$
  • B
    $1 \div\left\{\left(\frac{5}{6}\right)^{1 / 5}\right\}^{1 / 6}$
  • C
    $\left(\frac{6}{5}\right)^{\frac{1}{30}}$
  • D
    $\left(\frac{5}{6}\right)^{-\frac{1}{30}}$

Answer: A.

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Q 2M.C.Q1 Mark
Which of the following is equal to x?
  • A
    $x^{\frac{12}{7}}-x^{-\frac{5}{7}}$
  • B
    $\sqrt[12]{\left(x^4\right)^{1 / 3}}$
  • $\left(\sqrt{x^3}\right)^{2 / 3}$
  • D
    $x^{\frac{12}{7}} \times x^{\frac{7}{12}}$

Answer: C.

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Q 4M.C.Q1 Mark
The product $\sqrt[3]{2} \times \sqrt[4]{2} \times \sqrt[12]{32}$ equals
  • A
    $\sqrt{2}$
  • 2
  • C
    $\sqrt[12]{2}$
  • D
    $\sqrt[12]{32}$

Answer: B.

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Statement-1 (A): $\sqrt{\frac{81}{64} \sqrt{\frac{81}{64} \sqrt{\frac{81}{64} \sqrt{\frac{81}{64}}}}} \cdots \cdot x=\frac{9}{8}$,
Statement-2 (R): For any positive real number $x: \sqrt{x \sqrt{x \sqrt{x \sqrt{x \sqrt{x}}}}} \ldots x=x$.
  • A
    Statement-1 and Statement-2 are True; Statement-2 is a correct explanation for Statement-1
  • B
    Statement-1 and Statement-2 are True; Statement-2 is not a correct explanation for Statement-1
  • C
    Statement-1 is True, Statement-2 is False
  • D
    Statement-1 is False, Statement-2 is True
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Statement-1 (A): $\sqrt{7 \sqrt{7 \sqrt{7 \sqrt{7}}}}=\sqrt[16]{7^{15}}$.
Statement-2 (R): $\sqrt{a \sqrt{a \sqrt{a \ldots \ldots \ldots .}}} n$ terms $=a^{\frac{2^n-1}{2^n}}$.
  • Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.
  • B
    Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.
  • C
    Statement-1 is true, Statement-2 is false.
  • D
    Statement-1 is false, Statement-2 is true.

Answer: A.

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Statement-1 (A): $\sqrt{6+\sqrt{6+\sqrt{6+\sqrt{6+}}}} \ldots \ldots \ldots \ldots \infty=3$.
Statement-2 (R): $\sqrt{x+\sqrt{x+\sqrt{x+}}} \ldots \ldots \ldots \ldots \infty=x, x>0$.
  • A
    Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.
  • B
    Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.
  • Statement-1 is true, Statement-2 is false.
  • D
    Statement-1 is false, Statement-2 is true.

Answer: C.

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Statement-1 (A): $\sqrt{5 \sqrt{5 \sqrt{5 \sqrt{5}}}} \cdots \cdots \ldots \ldots=5 \sqrt{5}$.
Statement-2 (R): $\sqrt{x \sqrt{x \sqrt{x \sqrt{x}}}} \ldots \ldots \ldots \ldots \infty=x, x>0$.
  • A
    Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.
  • B
    Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.
  • C
    Statement-1 is true, Statement-2 is false.
  • Statement-1 is false, Statement-2 is true.

Answer: D.

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Statement-1 (A): $\left[\left\{\left(\frac{1}{7^2}\right)^{-2}\right\}^{-1 / 3}\right]^{1 / 4}=7^{-1 / 3}$
Statement-2 (R): $\left(\left(a^m\right)^n\right)^s=a^{m n s}, a>0$
  • Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.
  • B
    Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.
  • C
    Statement-1 is true, Statement-2 is false.
  • D
    Statement-1 is false, Statement-2 is true.

Answer: A.

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Simplify:
$\Big(\frac{\text{x}^{\text{a}+\text{b}}}{\text{x}^\text{c}}\Big)^{\text{a}-\text{b}}\Big(\frac{\text{x}^{\text{b}+\text{c}}}{\text{x}^\text{a}}\Big)^{\text{b}-\text{c}}\Big(\frac{\text{x}^{\text{c}+\text{a}}}{\text{x}^\text{b}}\Big)^{\text{c}-\text{a}}$
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Simplify:

$\sqrt[\text{lm}]{\frac{\text{x}^\text{l}}{\text{x}^\text{m}}}\times\sqrt[\text{mn}]{\frac{\text{x}^\text{m}}{\text{x}^\text{n}}}\times\sqrt[\text{nl}]{\frac{\text{x}^\text{n}}{\text{x}^\text{l}}}$

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