ABCD is a rhombus. The coordinates of A and C are $(3,6)$ and $(-1,2)$ respectively. Write down the equation of BD .
View full solution →Question types
Equation of Triangles question types
39 questions across 4 question groups — pick any mix to generate a Mathematics paper with step-by-step answer keys.
39
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Sample Questions
Equation of Triangles questions
One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
(a) The line $4 x-3 y+12=0$ meets the $x$-axis at A . Write down the coordinates of A .
(b) Determine the equation of the line passing through A and perpendicular to $4 x-3 y+12=0$.
View full solution →(b) Determine the equation of the line passing through A and perpendicular to $4 x-3 y+12=0$.
Find the equation of a line passing through the point $(-2,3)$ and having the $x$-intercept of 4 units.
View full solution →Write down the equation of the line whose slope is $\frac{3}{2}$ and which passes through the point P , where P divides the line segment joining $A (-2,6)$ and $B (3,-4)$ in the ratio $2: 3$.
View full solution →$P(3,4), Q(7,-2)$ and $R(-2,-1)$ are the vertices of $\triangle P Q R$. Write down the equation of the median of the triangle through R .
View full solution →A and B are two points on the $x$-axis and $y$-axis respectively. $P (2,-3)$ is the mid point of AB . Find the
(a) coordinates of A and B .
(b) slope of line AB .
(c) equation of line $A B$.
View full solution →(a) coordinates of A and B .
(b) slope of line AB .
(c) equation of line $A B$.
Points A and B have coordinates $(7,-3)$ and $(1,9)$ respectively. Find:
(a) the slope of AB .
(b) the equation of the perpendicular bisector of the line segment AB .
(c) the value of $p$ if $(-2, p)$ lies on it.
View full solution →(a) the slope of AB .
(b) the equation of the perpendicular bisector of the line segment AB .
(c) the value of $p$ if $(-2, p)$ lies on it.
Find the value of $p$ if the lines, $5 x-3 y+2=0$ and $6 x-p y+7=0$ are perpendicular to each other. Hence find the equation of a line passing through $(-2,-1)$ and parallel to $6 x-p y+7=0$.
View full solution →A line AB meets $x$-axis at A and $y$-axis at $B . P (4,-1)$ divides AB in the ratio 1 : 2.
(a) Find the coordinates of A and B.
(b) Find the equation of the line through P and perpendicular to AB .
View full solution →(a) Find the coordinates of A and B.
(b) Find the equation of the line through P and perpendicular to AB .
Find the equation of the perpendicular from the point $(1,-2)$ on the line $4 x-3 y-5=0$. Also, find the co-ordinates of the foot of the perpendicular.
View full solution →If the point $(a, 2 a)$ lies on the line $y=3 x-6$, then the value of $a$ is :
- A1
- B3
- C6
- D7
The equation of the line whose inclination is $45^{\circ}$ and which intersects the $y$-axis at the point $(0,-4)$ is :
- A$x-y=4$
- B$x+y=4$
- C$y-x=4$
- D$x-y=-4$
The angle of inclination of the line $\sqrt{3} x-y=1$, is :
- A$30^{\circ}$
- B$45^{\circ}$
- C$60^{\circ}$
- D$90^{\circ}$
The slope of the line $x-2 y=1$ is :
- A$0$
- B$1$
- C$\frac{1}{2}$
- D$-\frac{1}{2}$
The slope of a line parallel to the line $3 x+2 y-7=0$ is :
- A$-\frac{2}{3}$
- B$\frac{2}{3}$
- C$\frac{-3}{2}$
- D$\frac{3}{2}$
Assertion (A) : The slope of the line $2 y-5 x=3$ is given by $\frac{-5}{2}$.
Reason (R) : In $y=m x+c, m$ gives the slope of the line.
View full solution →Reason (R) : In $y=m x+c, m$ gives the slope of the line.
Assertion (A) : Slope of a line joining the points $(-4,1)$ and $(3,2)$ is $\frac{1}{7}$
Reason (R) : Gradient of a line is given by $m=\tan \theta$.
View full solution →Reason (R) : Gradient of a line is given by $m=\tan \theta$.
Assertion (A) : The line represented by the equation $2 y=-3 x$ passes through the origin.
Reason (R) : Any equation of the form $y=m x+c, c \neq 0$, passes through the origin.
View full solution →Reason (R) : Any equation of the form $y=m x+c, c \neq 0$, passes through the origin.
Assertion (A) : The slope of the line $y=-2$ is 0 .
Reason (R) : Slope of a line parallel to $x$-axis is 0 .
View full solution →Reason (R) : Slope of a line parallel to $x$-axis is 0 .
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